Using the Distributive Property 3(a + b) = 3a + 3b. To use the Distributive property, multiply the term on the outside of the parentheses by each term on the inside of the parentheses.
Answer:
1. (x+1)²
2. 6(x−1)
3. x = --√6--y/2 +1 x 6 = √6 - y/2 + 1, y
4. x = --√12 -- y -- 3 x =√12 -- y -- 3, y 12
5. −2x
6. 12x
7. x = -- √21 -- 6y/3 + 1 x = √21 -- 6y + 1, y 7/2
8. x =√2y + 7 -- 1 x = --√2y + 7 -- 1, y -- 7/2
- HOPE HELPS!
- <u><em>MARK AS BRAINLIEST</em></u>
- <u><em>ADD ME</em></u>
- <u><em>THIS WAS HARD FOR ME TO DO</em></u>
- <u><em>DONT HAVE A GOOD DAY </em></u>
- <u><em>HAVE A GREAT DAY!</em></u>
<u><em></em></u>
<u><em></em></u>
<u><em></em></u>
<u><em></em></u>
<u><em>Kayla-</em></u>
Answer:
-five sixths= -5/6
six fifths= 6/5
times= multiplication
so , -5/6 x 6/5 = -1
(both sixes get cancelled and the fives also get cancelled to get -1/1 = -1)
Answer:
![tan(\theta)=\sqrt{35}](https://tex.z-dn.net/?f=tan%28%5Ctheta%29%3D%5Csqrt%7B35%7D)
Step-by-step explanation:
we know that
The angle
lies in Quadrant III
so
The value of cosine is negative
The value of sine is negative
The value of tangent is positive
we have
![cos(\theta)=-\frac{1}{6}](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D-%5Cfrac%7B1%7D%7B6%7D)
step 1
Find the value of ![sin(\theta)](https://tex.z-dn.net/?f=sin%28%5Ctheta%29)
Applying trigonometric identity
![sin^2(\theta)+cos^2(\theta)=1](https://tex.z-dn.net/?f=sin%5E2%28%5Ctheta%29%2Bcos%5E2%28%5Ctheta%29%3D1)
substitute the given value
![sin^2(\theta)+(-\frac{1}{6})^2=1](https://tex.z-dn.net/?f=sin%5E2%28%5Ctheta%29%2B%28-%5Cfrac%7B1%7D%7B6%7D%29%5E2%3D1)
![sin^2(\theta)+\frac{1}{36}=1](https://tex.z-dn.net/?f=sin%5E2%28%5Ctheta%29%2B%5Cfrac%7B1%7D%7B36%7D%3D1)
![sin^2(\theta)=1-\frac{1}{36}](https://tex.z-dn.net/?f=sin%5E2%28%5Ctheta%29%3D1-%5Cfrac%7B1%7D%7B36%7D)
![sin^2(\theta)=\frac{35}{36}](https://tex.z-dn.net/?f=sin%5E2%28%5Ctheta%29%3D%5Cfrac%7B35%7D%7B36%7D)
square root both sides
![sin(\theta)=\pm\frac{\sqrt{35}}{6}](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D%5Cpm%5Cfrac%7B%5Csqrt%7B35%7D%7D%7B6%7D)
Remember that the sine is negative (Quadrant III)
so
![sin(\theta)=-\frac{\sqrt{35}}{6}](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D-%5Cfrac%7B%5Csqrt%7B35%7D%7D%7B6%7D)
step 2
Find the value of ![tan(\theta)](https://tex.z-dn.net/?f=tan%28%5Ctheta%29)
we know that
![tan(\theta)=\frac{sin(\theta)}{cos(\theta)}](https://tex.z-dn.net/?f=tan%28%5Ctheta%29%3D%5Cfrac%7Bsin%28%5Ctheta%29%7D%7Bcos%28%5Ctheta%29%7D)
we have
![sin(\theta)=-\frac{\sqrt{35}}{6}](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D-%5Cfrac%7B%5Csqrt%7B35%7D%7D%7B6%7D)
![cos(\theta)=-\frac{1}{6}](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D-%5Cfrac%7B1%7D%7B6%7D)
substitute
![tan(\theta)=-\frac{\sqrt{35}}{6}:-\frac{1}{6}=\sqrt{35}](https://tex.z-dn.net/?f=tan%28%5Ctheta%29%3D-%5Cfrac%7B%5Csqrt%7B35%7D%7D%7B6%7D%3A-%5Cfrac%7B1%7D%7B6%7D%3D%5Csqrt%7B35%7D)
Answer: x=4
Step-by-step explanation: