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natali 33 [55]
3 years ago
9

Machines a and t were both cleaned this week machine a is cleaned every 12 weeks and machine t is cleaned every 8 weeks what is

the fewest number of weeks that will pass before both machines are cleaned again in the same week. Please show work LCM
Mathematics
2 answers:
Mice21 [21]3 years ago
7 0
12x2=24 8x3=24 , so all you needed was to multiply the week until you got the same answer for both
Gennadij [26K]3 years ago
3 0

Answer:

The fewest number of weeks that will pass before both machines are cleaned again in the same week is 24 weeks.

Step-by-step explanation:

Given : Machines a and t were both cleaned this week machine a is cleaned every 12 weeks and machine t is cleaned every 8 weeks.

To find : What is the fewest number of weeks that will pass before both machines are cleaned again in the same week ?

Solution :

According to question,

We have take LCM of the numbers 12 and 8.

2 | 8  12

2 | 4   6

2 | 2   3

3 | 1   3

  | 1   1

LCM(8,12)=2\times 2\times 2\times 3

LCM(8,12)=24

Therefore, the fewest number of weeks that will pass before both machines are cleaned again in the same week is 24 weeks.

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Step-by-step explanation:

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area of base (considering that you use 2r square)  is 4r²

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ratio   h /r  =  12.74/5         h /r  =  2.55

   

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