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garik1379 [7]
3 years ago
15

Write the equation of the line with a slope of -6 and passing through the point (-2,1)

Mathematics
1 answer:
Arlecino [84]3 years ago
5 0
Y = mx + b
y = -6x + b
1 = -6 (-2) + b
1 = 12 + b

b = -11

y = -6x - 11
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<u>H</u><u>e</u><u>y</u><u> </u><u>M</u><u>a</u><u>t</u><u>e</u><u>!</u><u> </u><u>H</u><u>e</u><u>r</u><u>e</u><u>'</u><u>s</u><u> </u><u>y</u><u>o</u><u>u</u><u>r</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>.</u>

Step-by-step explanation:

<em><u>One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25</u></em>

<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32</u></em>

<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35</u></em>

<em><u>Total ingradiants for one packet of biscuits =</u></em>

<em><u>Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625</u></em>

<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =</u></em>

<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32</u></em>

Hope it helped you!

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