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Zepler [3.9K]
3 years ago
7

URGENT!!!!!

Mathematics
1 answer:
Marysya12 [62]3 years ago
8 0
Remember the pythagorean theorem?
this is like that
the distance is the hypotnuse

D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

D=\sqrt{(8-(-3))^{2}+(-7-4)^{2}}
D=\sqrt{(11)^{2}+(-11)^{2}}
D=\sqrt{169+169}
D=\sqrt{338}
D=11\sqrt{2}
aprox 15.55 units



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Solve for x in the equation x^2-4x-9=29? x=2+/- squareroot 42 x=2+/-squareroot 33 x=2+/-squareroot 34 x=4+/-squareroot 42
jeka57 [31]
For this case what we must do is to use the formula of the resolvent in the following way:
 x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
 Where,
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 Substituting the values:
 x = (- (- 4) +/- root ((- 4) ^ 2 - 4 * 1 * (- 38))) / (2 * 1)
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mash [69]
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viktelen [127]

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So the slope is 4,

y-3=4(x-10)

6 0
4 years ago
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