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3 years ago

URGENT!!!!!

1 answer:

8 0

Remember the pythagorean theorem?
this is like that
the distance is the hypotnuse

D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

D= $\sqrt{(8-(-3))^{2}+(-7-4)^{2}}$
D= $\sqrt{(11)^{2}+(-11)^{2}}$
D= $\sqrt{169+169}$
D= $\sqrt{338}$
D= $11\sqrt{2}$
aprox 15.55 units

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Calculate the interest amount for a loan of $800 at 4.25% simple interest for 6 years.

Andrei [34K]

Answer:

I= PRT/100

= 800 X 4.25 X 6 /100

= 20400/100

I=204

Interest amount: $204

3 0

3 years ago

Find sin angle∠ A. A. 3/5 B. 4/5 C. 1 D. 5/4

Rzqust [24]

Answer:

The answer is B.

Step-by-step explanation:

Recall SohCahToa, where $sin(A)=opp/hyp$ .

The opposite side (to angle A) here is 8, while the hypotenuse is 10.

Thus, we have:

$sin(A)=8/10=4/5$

The correct answer is B.

8 0

3 years ago

The sides of a rectangle are 3t - 2 and 5t + 7. Write an expression for the perimeter of the rectangle.

natka813 [3]

How does this have anything to do with factoring?
Perimeter of the rectangle would just be 2(3t-2)+2(5t+7)
Simplify that to get 6t-4+10t+14, then 16t+10

6 0

3 years ago

X-20 = y+20 2Y - 44 = X + 22

nordsb [41]

X-20 = Y+20........ X-Y = 20+20........

X-Y = 40

AND

2Y-44=X+22............. Y-X= 44+22

Y-X=66

NOW, LET'S FIND X AND Y FROM THESE TWO EQUATIONS....

X-Y =40

Y-X= 66

IF WE COLLECT ....... 2Y = 106 AND Y = 53

THEN, USE Y IN ANY EQUATIONS FOR FINDING X

X-53 = 40 ..... X= 53+40 .......... X= 93

X= 93

Y=53

8 0

3 years ago

Find each variable please!!!

elena-14-01-66 [18.8K]

Answer:

x = 6.5

Step-by-step explanation:

By property of intersecting secants outside of circle.

$6(6 + x) = 5(5 + 10) \\ 36 + 6x = 5 \times 15 \\ 6x = 75 - 36 \\ 6x = 39 \\ x = \frac{39}{6} \\ x = \frac{13}{2} \\ x = 6.5$

8 0

3 years ago