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2 years ago

Deepak wrote out the steps to his solution of the equation – 3x – 5 + 4x = –.

Mathematics

1 answer:

MrMuchimi2 years ago

3 0

X=5 if that's what you were asking for

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Jane spent $48 on her mom's Christmas gift. This is 55% of the total money she has saved. How much does Jane have saved?

Artist 52 [7]

Answer: 86

Step-by-step explanation: 96 is 105 we need find 100% so we need to find per percent

4 0

1 year ago

HELP PLEASE! FAST! WILL GIVE 5 STARS AND THANKS!<br> 5/6 x 18

Yuri [45]

Answer:

Step-by-step explanation:

5/6 * 18

Rearranging

5 * 18/6

5 *3

3 0

2 years ago

How many groups of 1/2 days are in 1 week? Write a multiplication equation or a division equation to represent the question, the

worty [1.4K]

Answer:

14 groups

Step-by-step explanation:

Given

$Groupings = \frac{1}{2}\ day$

$Duration = 1\ week$

Required

Determine the number of group in the week

To do this, we simply divide the duration by the number half day group.

This gives:

$Group = \frac{Duration}{Groupings}$

$Group = \frac{1\ week}{1/2\ days}$

Convert week to days

$Group = \frac{7\ days}{1/2\ days}$

$Group = \frac{7}{1/2}$

$Group = 7 / \frac{1}{2}$

Convert to multiplication

$Group = 7 * \frac{2}{1}$

$Group = \frac{14}{1}$

$Group = 14$

<em>Hence, there are 14 groups</em>

4 0

2 years ago

Plot the intercepts to graph the equation

natulia [17]

Jsjdhdjsjensbejejdndnsksbdjendkebfkendntjd

8 0

2 years ago

Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are

Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

$P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}$ .

Recall that $\binom{n}{k}= \frac{n!}{k!(n-k)!}$ In this case, the student passes if X is at least four correct questions, then

$P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696$

c)The expected value of a binomial random variable with parameters n and p is $E[X] = np$ . IN our case, n=6 and p =0.2. Then the expected value of correct answers is $6\cdot 0.2 = 1.2$

5 0

3 years ago