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nikitadnepr [17]

3 years ago

14

Lee needed to make full length curtains to fit from the top of the window to the floor. The wall beneath the window had the heig

ht of 2 2/3 feet and the height of just the window measured 2 3/4 feet. How long do the curtains have to be?

1 answer:

worty [1.4K]3 years ago

7 0

Add the 2 together
2 2/3 + 2 3/4 you need a common denominator to add fractions
2 8/12 + 2 9/12 = 4 17/12 =
5 5!12 feer

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The Florida Everglades welcomes about

Bingel [31]

Answer:

14,000 visitors weekly

Step-by-step explanation:
Break the Equation Down.

10^3 = 10 x 10 x 10

10x10x10=1000 V

Put the 1000 within the problem.

2 x 1000

Solve

2 x 1000 = 2000 Visitors

7 days are within a week so multiply the daily visitors (2000) by 7

2000 x 7 = 14,000

Answer: 14,000 visitors weekly

Hope you like this way of solving! Let me know if have any questions!

3 0

2 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

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3 years ago

Find the perimeter of this shape

telo118 [61]

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3 years ago

5x - 4y = 0 in point intercept form

Contact [7]

Answer:

in slope-intercept form y = 5/4x in y-intercept form is b = 0. try to use math___way dot com

Step-by-step explanation:

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Which of the following measurements, in centimeters (cm), could be the lengths of the sides of a triangle? Select all that apply

monitta

The answer is
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