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melamori03 [73]
2 years ago
5

Help please!!!!!!!!!

Mathematics
1 answer:
REY [17]2 years ago
7 0

Since all triangle's angle's values add up 180 degrees, this means we have to make sure to angles add up to 180.

A. 75 + 35 = 110. 180 - 110 = 70 degrees.

B. This triangle is isosceles meaning 2 of its sides is the same length. In this case, the two sides add up to 140 (meaning they are both 70 degrees). 180 - 140 =  40 degrees.

C. I sadly don't know how to solve it.

D. This is another isosceles triangle. 180 - 36 = 144.

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PLEASE HELP. <br> I know how to do these but I'm stuck on this one.
Nezavi [6.7K]

Steve ran 11 miles

let the distance Steve ran be x

Then distance Kevin ran is x + 4 ( 4 miles more than Steve )

x + x + 4 = 26 ( the sum of their distance is 26 )

2x + 4 = 26 ( subtract 4 from both sides )

2x = 22 ( divide both sides by 2 )

x = 11

Steve ran 11 mies and Kevin ran 11 + 4 = 15 miles

check 11 + 15 = 26


5 0
3 years ago
Could really use some help <br>​
MrRissso [65]
Answer:
X= 114
I don’t know what y is labeling so I won’t be able to help there sorry
5 0
2 years ago
What number is missing from the rule table
mr_godi [17]
C. 7. because if you divide the value for the missing term (take 28 for example) and divided it by the value of i (4) you will get 7. (28÷4=7)
3 0
3 years ago
The sum of four times a number and five times another number is -28. The sum of nine times the first number and two times the se
Rina8888 [55]

Answer:

<h2>3 and -8</h2>

Step-by-step explanation:

x,\ y-the\ numbers\\\\\text{The sum of four times a number and five times another number is -28:}\\\\4x+5y=-28\\\\\text{The sum of nine times the first number and two times the second number is 11:}\\\\9x+2y=11\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}4x+5y=-28&\text{multiply both sides by2}\\9x+2y=11&\text{multiply both sides by (-5)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}8x+10y=-56\\-45x-10y=-55\end{array}\right}\qquad\text{add both sides of the equation}

.\qquad-37x=-111\qquad\text{divide both sides by (-37)}\\.\qquad\qquad\boxed{x=3}\\\\\text{Put the value of x to the first equation:}\\\\4(3)+5y=-28\\12+5y=-28\qquad\text{subtrac 12 from both sides}\\5y=-40\qquad\text{divide both sides by 5}\\\boxed{y=-8}

3 0
2 years ago
Please help 7n = 63 <br> n = ____
Whitepunk [10]

7 x 9 = 63

Hope this Helped:)))

6 0
3 years ago
Read 2 more answers
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