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guapka [62]
2 years ago
10

A box of donuts containing 6 maple bars, 3 chocolate donuts, and 3 custard filled donuts is sitting on a counter in a work offic

e. Warren comes along and decides to eat two in a row. What is the probability that Warren will eat a chocolate donut and then a custard filled donut
Mathematics
1 answer:
Svetlanka [38]2 years ago
7 0

Probabilities are used to determine the chances of selecting a kind of donut from the box.

The probability that Warren eats a chocolate donut, and then a custard filled donut is 0.068

The given parameters are:

\mathbf{Bars = 6}

\mathbf{Chocolate = 3}

\mathbf{Custard= 3}

The total number of donuts in the box is:

\mathbf{Total= 6 + 3 + 3}

\mathbf{Total= 12}

The probability of eating a chocolate donut, and then a custard filled donut is calculated using:

\mathbf{Pr = \frac{Chocolate}{Total}\times \frac{Custard}{Total-1}}

So, we have:

\mathbf{Pr = \frac{3}{12}\times \frac{3}{12-1}}

Simplify

\mathbf{Pr = \frac{3}{12}\times \frac{3}{11}}

Multiply

\mathbf{Pr = \frac{9}{132}}

Divide

\mathbf{Pr = 0.068}

Hence, the probability that Warren eats a chocolate donut, and then a custard filled donut is approximately 0.068

Read more about probabilities at:

brainly.com/question/9000575

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