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shepuryov [24]
3 years ago
14

If h(x) = x – 7 and g(x) = x2, which expression is equivalent to (g circle h) (5)?

Mathematics
2 answers:
Tema [17]3 years ago
8 0
<h3>Answer:  4</h3>

=====================================================

Work Shown:

(g \circ h)(x) = g(h(x))

g(x) = x^2\\\\g(h(x)) = (h(x))^2 \ \text{replace every x with h(x)}\\\\g(h(x)) = (x-7)^2 \ \text{replace h(x) with x-7}\\\\(g \circ h)(x) = (x-7)^2

Now plug in x = 5

(g \circ h)(x) = (x-7)^2 \\\\(g \circ h)(5) = (5-7)^2 \\\\(g \circ h)(5) = (-2)^2\\\\ (g \circ h)(5) = 4

---------------------

Alternative approach:

h(x) = x-7

h(5) = 5-7

h(5) = -2

So this means

g(h(5)) = g(-2)

and

g(x) = x^2

g(-2) = (-2)^2

g(-2) = 4

Therefore making

g(-2) = g(h(5)) = (g \circ h)(5) = 4

Contact [7]3 years ago
5 0

Answer:

(5 – 7)2

Step-by-step explanation:

(5 – 7)2 equals 4

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