Answer:
$3
Step-by-step explanation:
Because you have to also think about tax of the item. Plus add them both up and it costs $2.24 without tax. Which means it's already above $2.
Answer:
y=-3/2x+6
Step-by-step explanation:
You can find the slope by taking two points on the graph, and making the one that occurs earlier in the graph (from left to right) the first point (x1, y1) and the one that occurs later in the graph the second point (x2, y2). The equation is m (or slope)=(y2-y1)/(x2-x1). I took the first two points in the table for this. m=(12-18)/-4-(-8)
the double negative on the bottom becomes an addition=> (12-18)/(-4+8)
the top simplifies to be -6 and the bottom simplifies to 4=>-6/4
this fraction can be reduced to -3/2, which is the slope of the graph.
Now, use point slope form (y-y1=m(x-x1)) to find the equation of the graph. Plug any coordinate on the graph in for x1 and y1 here. It should be correct as long as it is a point on the graph, but I am using the point (-8, 18) here.
=>y-18=-3/2(x-(-8))
the double negative in the parentheses becomes a positive=> y-18=-3/2(x+8)
distribute the -3/2 to every term in the parentheses=> y-18=-3/2x-12
add 18 to both sides, cancelling out the -18 on the left side of the equation=>y=-3/2x+6 (-12+18=6 to get 6 for b).
Therefore, the equation is y=-3/2x+6
The answer is 180 degrees. The rotation that maps one side
to an adjacent side is 360°/6 = 60°. This is the least rotation that plots
the regular hexagon to the aforementioned. In the least whole number of these
minimum rotations,
such as three 60° rotations to make 180°, will retain
the hexagon identical.
Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 
is 
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given
Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.
Substituting m1 we get m2 as
Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line is
