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3 years ago

4 m / h = cm min helppp

Mathematics

1 answer:

xenn [34]3 years ago

5 0

Answer:

6.6 repeating cm per min

Step-by-step explanation:

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*<br> E<br> Which angle is an acute angle?

vodomira [7]

Answer:

angle COD is right answer

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3 years ago

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Pete and Teegan each put the same amount of money in a new bank account. Teegan's account earns 2.75% simple interest, and she e

torisob [31]

Answer:

$4.

Step-by-step explanation:

Let us assume that Pete and Teegan each put an amount of $P in a new bank account.

Teegan's account earns 2.75% simple interest and she earned $2.20 in interest after one year.

So, we can write $\frac{P \times 2.75}{100} = 2.20$

⇒ P = $80

Now, this $80 in Pete's account earns 5% simple interest.

Then after one year Pete will earn as interest $\frac{80 \times 5}{100} = 4$ Dollars. (Answer)

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3 years ago

The weight distribution of parcels sent in a certain manner is normal with mean of 12 lb and standard deviation of 3 lb. The par

kicyunya [14]

Answer:

21.16

Step-by-step explanation:

Starting from the theory we have the following equation:

$fi*P(x$

Using the data supplied in the exercise, we have subtracting the mean and dividing by the standard deviation:

$P( z \leq \frac{c-1-12}{3.5}) =0.99/fi$

solving for "c", knowing that fi is a tabulating value:

$\frac{c-13}{3.5}=0.99/fi\\\frac{c-13}{3.5}=2.33\\c-13=2.33*3.5\\c = 8.155 +13\\c = 21.155$

therefore the value of c is equal to 21.16

8 0

3 years ago

A department store is having a sale of 20% off of all kitchen appliances. What is the sale price for a $250 microwave?

IgorC [24]

Answer:

200

Step-by-step explanation:

The price is 100%-20%=80% of the original.

So, 250*0.8 = 200

3 0

3 years ago

Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$

Anna [14]

Answer:

$\large\boxed{1\dfrac{1}{3}\ u^2}$

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

$x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1$

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

$\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}$

6 0

3 years ago

4 m / h = cm min helppp​

4 m / h = cm min helppp