Answer:
And we can do a similar procedure for the sea water:
And after convert the volume to m^3 we got:
And then the density for the mixture would be given by:
And replacing we got:
Step-by-step explanation:
For this case we can begin calculating the mass for each type of water:
And after convert the volume to m^3 we got:
And we can do a similar procedure for the sea water:
And after convert the volume to m^3 we got:
And then the density for the mixture would be given by:
And replacing we got:
First of all we have to find the slope by this relation
y₂-y₁
———
x₂-x₁
0-0
———
-6 + 3
= 0
so the slope is 0
y-y₁ = m (x-x₁)
y-0 = 0 (x-0)
y = 0
Answer:
Part A) The surface area of prism B is equal to the surface area of prism A multiplied by the scale factor (m) squared
Part B) The Volume of prism B is equal to the Volume of prism A multiplied by the scale factor (m) elevated to the cube
Step-by-step explanation:
Part A) we know that
The scale factor is equal to m
The surface area of the prism is equal to
where
B is the area of the base
P is the perimeter of the base
h is the height of the prism
we have
Prism A
substitute
Prism B
substitute
therefore
The surface area of prism B is equal to the surface area of prism A multiplied by the scale factor (m) squared
Part B) we know that
The volume of the prism is equal to
where
B is the area of the base
h is the height of the prism
we have
Prism A
substitute
Prism B
substitute
therefore
The Volume of prism B is equal to the Volume of prism A multiplied by the scale factor (m) elevated to the cube
5 of the planets are earth like and 2 are mars like
5 * 2 = 10
<u>1 * 2 = 2</u>
Total 12
4 earth like and 4 mars like
Earth = 4*2 = 8
<u>Mars = 4 * 1 = 4</u>
Total 12
3 Like Earth 6 like mars
Earth 3 * 2 = 6
<u>Mars 6 * 1 = 6</u>
Total 12
Those answers are the only ones possible.
It would be 2,112 yards = 1.2 miles