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deff fn [24]
4 years ago
7

sonia has 120 blocks. she decides to stack up all the blocks so that each row has one less block than the row below. She wants t

o end up with just 1 block on top. How many blocks should she put in the bottom row?
Mathematics
1 answer:
Leona [35]4 years ago
3 0

Answer:

15 blocks

Step-by-step explanation:

Step 1

This is an Arithmetic sequence. We are using the formula below.

aₙ = a + ( n - 1) d ..........Equation 1

Where:

a = First term

d = Common difference

n = number of term

We are told in the question that each row has one less block

Therefore,

aₙ = 1

d = -1 ( one less block)

a = a

aₙ = a + ( n - 1) d

1 = a + ( n - 1) -1

1 = a + ( -n + 1)

1 = a - n +1

a - n + 1 - 1 = 0

a - n = 0

a = n

Therefore, a = n

Step 2

The next step would be to solve the question using the sum of the arithmetic sequence formula

Sn = n/2( a + 1) ........ Equation 2

Where these values have already been given in the question

Sn = 120

a = n ( from the first step)

We are to solve for a

We would substitute n for a in Equation 2

Therefore, we have

Sn = n/2( a + 1)

120 = a/2(a + 1)

Cross multiply

120 × 2 = a(a + 1)

240 = a² + a

a² + a - 240 = 0

Using factorisation to solve the quadratic equation

a² -15a +16a -240 = 0

(a² - 15a) + (16a -240) = 0

a(a -15) + 16(a - 15) = 0

Hence, we have

(a- 15) (a + 16) = 0

a - 15 = 0

a = 15

a + 16 = 0

a = - 16

a = 15, -16

We pick the positive number, which is a = 15

Therefore, the number of blocks Sonia  should put in the bottom row is 15 blocks.

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