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prisoha [69]
2 years ago
15

BCDE is a parallelogram.What is the measure of <BEC​

Mathematics
1 answer:
Arlecino [84]2 years ago
8 0
The measure is 90 if correct
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Evaluate the expression. 33 + 35 - 8 x (16 ÷ 4)
Mila [183]

Answer:

−32x+68

Step-by-step explanation:

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7 0
2 years ago
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Find the value of r in (4, r), (r, 2) so that the slope of the line containing them is −53
Elan Coil [88]

Answer:

C) 7

===========================================

Work Shown:

Use the slope formula

m = (y2-y1)/(x2-x1)

Plug in the given slope we want m = -5/3 and also the coordinates of the points. Then isolate r

m = (y2-y1)/(x2-x1)

-5/3 = (2-r)/(r-4)

-5(r-4) = 3(2-r) .... cross multiplying

-5r+20 = 6-3r

-5r+20+5r = 6-3r+5r .... adding 5 to both sides

20 = 6+2r

20-6 = 6+2r-6 ....subtracting 6 from both sides

14 = 2r

2r = 14

2r/2 = 14/2 .... dividing both sides by 2

r = 7

The slope of the line through (4,7) and (7,2) should be -5/3, let's check that

m = (y2-y1)/(x2-x1)

m = (2-7)/(7-4)

m = -5/3

The answer is confirmed

7 0
3 years ago
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Plot the inequality on the number line​
maksim [4K]

Answer:

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3 years ago
In ∆MNP, m∠N = 90º, NH – altitude, m∠P = 21º, PM = 4 cm. Find MH.
Sveta_85 [38]

Answer:

0.51 cm

Step-by-step explanation:

In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°

By the sine definition,

\sin \angle P=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{MN}{MP}\\ \\MN=MP\sin \angle P\\ \\MN=4\sin 21^{\circ}\approx 1.43\ cm

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

\cos \angle M=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{MH}{MN}\\ \\MH=MN\cos \angle M

In the right triangle, two acute angles are always complementary, so

m\angle M=90^{\circ}-m\angle P=90^{\circ}-21^{\circ}=69^{\circ}

Thus,

MH=1.43\cos 69^{\circ}\approx 0.51\ cm

7 0
2 years ago
Eleven students are competing in an art contest. In how
KatRina [158]

Hi there

I think I may have the answer for you!

<u>Answer:</u>

<u />

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.

Please make sure to check my answer and mark it/

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