$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

3 years ago

Pls I need help I'm soooooooooooo confused on my question also please no links because I can't get to them!

saul85 [17]

Answer:

divide the least common denominator by the original denominator

6 0

3 years ago

Read 2 more answers

A cube has the dimensions shown. What is the volume of the cube?

bagirrra123 [75]

Sorry this is a tricky one IDK I'll ask some others to help you

5 0

3 years ago

Read 2 more answers

What is the step by step of<br> 1/ cos x csc^2 x = sin x/ cot x

Effectus [21]

Answer:

what is the step by step of 1/ cos x csc^2 x = sin x/ cot x

Step-by-step explanation:

csc

sin

cot

cos

sin

Given,

−

cos

sin

csc

−

cot

Simplify the right side.

csc

−

cot

sin

−

cos

sin

−

cos

sin

∴

, LS

RS.

7 0

3 years ago