Answer:
15^3−31^2+20−4
Step-by-step explanation:
Distribute
(3−2)(5^2−7+2)
3(5^2−7+2)−2(5^2−7+2)
Distribute
3(52−7+2)−2(5^2−7+2)
15^3−21^2+6−2(5^2−7x+2)
Distribute
15^3−21^2+6−2(5^2−7+2)
15^3−21^2+6−10^2+14−4
Combine like terms
15^3−21^2+6−10^2+14−4
15^3−31^2+6+14−4
Combine like terms
15^3−31^2+6+14−4
15^3−31^2+20−4
Solution
15^3−31^2+20−4
Answer:
TC recheck it hexes ten 8 Uzbek
Using the Emperical rule:
68% lie with one one standard deviation:
16 + 1.7 , 16-1.7 = 17.7, 14.3
14.3 is part of the 68%.
The remaining 32% of the distribution is outside the range, with half being less than and half being greater than.
32/2 = 16
The probability of living loner than 14.3 Would be 16%
Answer:
x=−11
Step-by-step explanation:
7+5(x−3)=7(x+2)
Step 1: Simplify both sides of the equation.
7+5(x−3)=7(x+2)
7+(5)(x)+(5)(−3)=(7)(x)+(7)(2)(Distribute)
7+5x+−15=7x+14
(5x)+(7+−15)=7x+14(Combine Like Terms)
5x+−8=7x+14
5x−8=7x+14
Step 2: Subtract 7x from both sides.
5x−8−7x=7x+14−7x
−2x−8=14
Step 3: Add 8 to both sides.
−2x−8+8=14+8
−2x=22
Step 4: Divide both sides by -2.
−2x
−2
=
22
−2
x=−11