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3 years ago

Solve for x.... 2/7=x/13

Mathematics

1 answer:

Yuki888 [10]3 years ago

4 0

X/13 2/7
X=2/7*(13)
X=26/7 Final Answer

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How to solve this with tan<br> I need AB

sesenic [268]

Answer:

AB = 2.18 units

Step-by-step explanation:

$\tan 52\degree =\frac{AB}{BC} \\ \\ AB = BC \tan 52\degree \\ \\ AB = 1.7 \times 1.2799416322 \\ \\ AB = 1.7 \times 1.2799416322 \\ \\AB = 2.17590077 \\ \\ AB \approx 2.18 \: units$

5 0

3 years ago

The answers pls <br>and pls again

dlinn [17]

3. 27 because 18+9=27

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3 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

3 years ago

Create and solve a linear equation that represents the model, where squares and triangles are shown evenly balanced on a balance

Rina8888 [55]

Let the weight of triangle be x units. You are given that the weight of square is 1 unit.

1) On the left side of the balanced beam you can see 3 triangles and 5 squares. The weight on left side is 3·x+5·1=3x+5 units.

2) On the right side of the balanced beam you can see 2 triangles and 7 squares. The weight on right side is 2·x+7·1=2x+7 units.

3) If the whole system is balanced, then the weights on left and right sides are equal:

3x+5=2x+7.

Solve this equation:

3x-2x=7-5,

x=2 units.

Answer: option A

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3 years ago

Five billion, twenty-four million, five and six thousandths

Verizon [17]

Answer:

5,024,000,005.006

Step-by-step explanation:

This is the standard form of five billion, twenty-four million, five and six thousandths.

4 0

3 years ago

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