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3 years ago

If 50 is 20% of a value what is that value

Mathematics

2 answers:

ira [324]3 years ago

5 0

The answer would be 200 because it takes 20% 4x to get to 100% so 50x4=200

boyakko [2]3 years ago

4 0

The value would be 250.

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If I had 3000 pennies and my mom took away 1000 pennies how many are left

pishuonlain [190]

Subtract 3000-1000

took away means subtracting

left means how many are remaining

3000-1000= 2000

Answer:

2000 pennies

7 0

3 years ago

Read 2 more answers

4x + 10 = 2x - 14<br> Find the value of x.

Gre4nikov [31]

Answer:

x= -12

Step-by-step explanation:

Simplifying

4x + 10 = 2x + -14

Reorder the terms:

10 + 4x = 2x + -14

Reorder the terms:

10 + 4x = -14 + 2x

Solving

10 + 4x = -14 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.

10 + 4x + -2x = -14 + 2x + -2x

Combine like terms: 4x + -2x = 2x

10 + 2x = -14 + 2x + -2x

Combine like terms: 2x + -2x = 0

10 + 2x = -14 + 0

10 + 2x = -14

Add '-10' to each side of the equation.

10 + -10 + 2x = -14 + -10

Combine like terms: 10 + -10 = 0

0 + 2x = -14 + -10

2x = -14 + -10

Combine like terms: -14 + -10 = -24

2x = -24

Divide each side by '2'.

x = -12

Simplifying

x = -12

3 0

3 years ago

Read 2 more answers

What is 36838e÷592019339e

miskamm [114]

Answer:

Hi! Your answer is down below!

Step-by-step explanation:

Hope this helps!

Have a nice day <3

4 0

2 years ago

Read 2 more answers

Multiply.

KATRIN_1 [288]

The answer could be
-1287
im not sure

7 0

3 years ago

plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =

ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

4 0

3 years ago