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olchik [2.2K]
3 years ago
9

If 50 is 20% of a value what is that value

Mathematics
2 answers:
ira [324]3 years ago
5 0
The answer would be 200 because it takes 20% 4x to get to 100% so 50x4=200
boyakko [2]3 years ago
4 0
The value would be 250.
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(x+b/2a)^2-b^2-4ac/4a^2=0<br> What would be the steps to solve this equation?
Marina86 [1]
Go to the google search engine.. take your little fingers and copy and paste this into it. The result will pop up within its calculator.

4 0
4 years ago
20. What is the total cost of a $20 item after adding 5% sales tax?
marissa [1.9K]
<h3>Answer: Choice B</h3>

Work Shown:

1.05*20 = 21

The 1.05 represents an increase of 5% because

100% + 5% = 1.00 + 0.05 = 1.05

7 0
2 years ago
Find the annual percent increase or decrease that y = 0.35(2.3)x models. (1 point) A.230% increase B.130% increase C.30% decreas
ipn [44]

Answer: B. 130% increase


Step-by-step explanation:

Given function :  y=0.35(2.3)^x

If x represents the number of years, we have to determine the two values of y in consecutive terms to determine if the value of y increases or decreases after a year.


This function is equivalent to the exponential growth function


y=A(1+r)^x, where A=0.35 and (1+r)=2.3, [A= initial amount , r=annual percent increase]

Thus,

\Rightarrow\ r=2.3-1\\\Rightarrow\ r=1.3\\\Rightarrow\ r=1.3\times100\%=130\%

Hence, the annual percent increase is 130%.

8 0
3 years ago
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diamong [38]
Choice D X intercept = Y intercept
6 0
3 years ago
What is the inverse of this function?​
kolbaska11 [484]

Answer:

f^{-1}(x)=4x^2-3

Step-by-step explanation:

<u>The Inverse of a Function</u>

Given a function f(x), the inverse of f, called f^{-1}(x) is a function that satisfies:

f(f^{-1}(x))=x

The domain of f becomes the range of its inverse and vice-versa.

The procedure to find the inverse of the function is:

* Write the function as a two-variable equation:

* Solve the equation for x.

* Swap the variables

We are given the function:

\displaystyle f(x)=-\frac{1}{2}\sqrt{x+3}

Defined in the interval x ≥ -3

Note f is always negative, thus its range is f(x) ≤ 0

Now we find the inverse. Call y=f(x):

\displaystyle y=-\frac{1}{2}\sqrt{x+3}

Multiplying by 2:

\displaystyle 2y=-\sqrt{x+3}

Squaring both sides:

\displaystyle 4y^2=x+3

Subtracting 3:

\displaystyle 4y^2-3=x

Swapping variables:

y=4x^2-3

Thus:

\mathbf{f^{-1}(x)=4x^2-3}

The domain of the inverse is the range of f, thus x is restricted to

x ≤ 0

5 0
3 years ago
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