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son4ous [18]
2 years ago
15

Julia measured the high temperature in her town for one week. Using the chart below, find the mean absolute deviation for the hi

gh temperatures.
Be sure to show your work for finding:

the mean of the set of data
the distance of each number from the mean
the mean absolute deviation

Mathematics
2 answers:
Georgia [21]2 years ago
3 0
The mean is going to be 46 because it is in the middle
sveticcg [70]2 years ago
3 0
The mean of the set of the data is 4.742
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b

Step-by-step explanation:

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Write an expression that is equivalent to - 0.5(14a - 22) .
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\textsf{Hey \: there}

<h2>QUESTION</h2>

\mathsf{-0.5(14a - 22)}

<h2>FIRST YOU HAVE TO DISTRIBUTE:</h2>

\mathsf{(-0.5)(14a) + (-0.5)( -22)}

<h2>SOLVING FOR OUR ANSWER</h2>

\mathsf{(0.5)(14a) =  - 7a} \\   \\  \mathsf{( - 0.5)( - 22) = 11}

<h2 /><h2>NEW EQUATION/THE ANSWER YOU WERE LOOKING FOR </h2>

\boxed{ \bf{your \: answer:} \boxed{ \huge \textsf{  \bf- 7a  + 11}}} \checkmark

<h2>GOOD LUCK ON YOUR ASSIGNMENT AND ENJOY YOUR DAY!</h2>

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\dfrac{\frak{LoveYourselfFirst}}{:)}

<h2>SIDE NOTE: THE DISTRIBUTIVE FORMULA IS</h2>

\text{a(b + c)} \\  \text{a(b) + a(c)} \\ \text{a(b) = ab} \\  \text{a(c) = ac} \\ \text{ \underline{ = ab + ac}}

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5 0
3 years ago
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Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
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Answer:

468

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3,744/8=468

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Answer:

infinitely many

Step-by-step explanation:

12x + 1 = 3(4x + 1) - 2

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Subtract 12x from each side

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2 years ago
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