Answer:
t/8 + t/7 = 1
Step-by-step explanation:
Given in the question that,
time require for Jose to paint the house = 7 hours
time require for Brandon to paint the house = 8 hours
Suppose t means Full house painted.
<h3>
To solve the question we have to figure out how much each of them can paint in ONE hour.</h3>
7 hours----t
1 hour ---- t/7
8 hours----t
1 hour ---- t/8
<h3>
Equation</h3>
t/8 + t/7 = 1 (in one hour)
(7t + 8t)/8(7) = 1
15t/56 = 1
15t = 56
t = 56/15
t = 3.73 hours
Answer:
<h3>20.5 IS YOUR ANSWER,,,,,,,,,,,,,,,</h3>
Answer:
17 degrees
Step-by-step explanation:
So to find the answer you need to subtract. If the temp went down 22.1 degrees and it is -5.1 degrees you will subtract 22.1 - 5.1. This equals 17 degrees. You know the answer is correct because you can check your answer by adding: 5.1 + 17 = 22.1. We are disregarding the negative sign.
Answer:
6580cm
Step-by-step explanation:
The answer is 6580cm because....
Step one First let's figure out what the smaller shape's volume is. To do so we need to multiply ( LxWxH ) so 6x5x? it does not list what the height is so we know it has the same height as the larger shape and it's height is 14cm so we will use 14cm. 6x5x14=420cm
Step two Now lets find the Volume of the larger shape. So lets do LxWxH so Lx?x14 it does not give us the length so we need to add up all of the numbers along the line. We got 7cm then 5 from the bottom of the smaller shape and 10cm. all ads up to 22cm so 20x22x14=6160
Finally we add up the following shapes Volume which are 6160+420=6580cm
Answer:
We want to graph the inequality:
3x - 2y ≤ 6
The first step is to write this as a linear equation, to do it, we can isolate y in one side of the inequality.
3x ≤ 6 + 2y
3x - 6 ≤ 2y
(3/2)x - 6/2 ≤ y
(3/2)x - 3 ≤ y
or:
y ≥ (3/2)x - 3
Because we have the symbol ≥
The points on the line are solutions, then the first part is to graph the line:
y = (3/2)*x - 3
Next, we have:
y equal to or larger than (3/2)*x - 3
Then we need to shade all the region above that line.
The graph can be seen below.
