Solution: We are given:
μ=3.1,σ=0.5,n=50
We have to find P(Mean <2.9)
We need to first find the z score
z= (xbar-μ)/(σ/sqrt(n))
=(2.9-3.1)/(0.5/sqrt(50))
=(-0.2)/0.0707
=-2.83
Now we have to find P(z<-2.83)
Using the standard normal table, we have:
P(z<-2.83)=0.0023
Therefore the probability of the sample mean being less the 2.9 inches is 0.0023
1.1 71/72
2.5 17/70
3.35 41/51
There you go hope it helps
Answer:
Piazza's has the better deal per bag
Step-by-step explanation:
The answer is: [B]: " -10a + 6b² − 4b + 3 " .
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Explanation:
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Given:
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-2(5a − 3b²) − 4b + 3 ;
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"Use the distributive property [of multiplication] to expand the expression."
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Note the distributive property of multiplication:
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a(b + c) = ab + ac ;
a(b − c) = ab − ac ;
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So, we have: " -2(5a − 3b²) − 4b + 3 " ;
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Start with: " -2(5a − 3b²) " ;
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-2(5a − 3b²) = (-2*5a) − (-2*3b²) = (-10a) − (-6b²)
= -10a + 6b²
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→ Now, bring down the rest of the problem;
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-10a + 6b² − 4b + 3 ; which is: Answer choice: [B].
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