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Free_Kalibri [48]
3 years ago
8

A rectangle has an area of 36 square units. As the length and the width change, what do you know about their product? Is this le

ngth proportional to the width? Justify your reasoning.
Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0
Area = 36 = length*width

Then, while the area is constant the product length*width is constant.

Length and area are inversely related.

That means that to keep the same product (area), length vary in inverse proportion to width.

If you increase length, widht has to decrease to satisfy this relation:

width = 36/length

Of course, you can also say: length = 36 / width.
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Factor the polynomials of 25 x2-49x4
mezya [45]

Answer:

25x2-49x4= -146

Step-by-step explanation:

i just used calculator

8 0
3 years ago
Sam has purchased a $30,000 car for his business. The car depreciates 30% every year. What is the explicit formula for this sequ
Step2247 [10]
If your just figuring out how much the car depreciated just by driving off the lot new...1st year.
$30,000×.30=$9,000

$30,000- $9,000=$21,000.

just take the brand new value of the car multiplied by the .30% of the 1st depreciation...take that answer ($9,000) and subtract it from your orginal value of $31,000.

which gives you $21,000

8 0
3 years ago
Read 2 more answers
Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
3 years ago
Read 2 more answers
What is the answer please help no links no links please help
schepotkina [342]
180cm. The square is 6 x 6 = 36 and the triangles = 12 x 6 = 72 and then divide it by 2 = 36 multiply that by 5 and you get 180cm
7 0
3 years ago
Read 2 more answers
(5p-9)(5p-9) find each square
Iteru [2.4K]

Answer:

The square would be 25p^2 - 90p + 81

Step-by-step explanation:

To get this, use the FOIL method. In this, we multiply the first, outer, inner and last pairings.

First - Multiply the first number in each parenthesis.

5p * 5p = 25p^2

Outer - Multiply the outside numbers in each parenthesis.

5p * -9 = -45p

Inner - Multiply the inner numbers in each parenthesis.

-9 * 5p = -45p

Last = Multiply the last numbers in each parenthesis

-9 * -9 = 81

Now take all of those numbers and add together. Then simplify.

25p^2 - 45p - 45p + 81

25p^2 - 90p + 81

6 0
3 years ago
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