Answer:good for him
Step-by-step explanation:
Answer:
The correct answer is 54.
Answer:
C) 0 ≤ x ≤ 25
Step-by-step explanation:
We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300
A)x ≥ 0
Refer the graph
At x = 0
f(x)=300
On increasing the value of x , f(x) increases but at x = 12 it starts decreasing
So, x ≥ 0 can also have f(x)<300
So, Option A is wrong
B)−5 ≤ x ≤ 30
At x = -5
f(x) = 100
So, Option B is wrong since we require f(x) is greater or equal to 300
c)0 ≤ x ≤ 25
At x = 0
f(x)=300
At x = 12 , it starts decreasing
At x = 25
f(x)=300
So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25
D)All real numbers
At x = 30
f(x)=0
But we require f(x) greater or equal to 300
Hence Option C is true
Hello,
1: dom f=R
2: img f =R
3: 2x²-x-6=2(x²-2x/4+1/46)-6-1/8=2(x-1/4)²-49/8
Vertex=(1/4,-49,8)
4: roots are -3/2 and 2
2(x-1/4)²-49/8=1/8[(4x-1)²-49]=1/8*(4x+6)(4x-8)
5:
From the vertex to ∞
[-1/4 , ∞)