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igor_vitrenko [27]
3 years ago
12

Suppose that Y and Z are points on a number line if YZ=20 and Y lies at 3 where could Z be located

Mathematics
1 answer:
creativ13 [48]3 years ago
5 0
17? probably I think
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Divide the Unit Rate $51 in 6 Hours ?
Lena [83]
Hello.

To find the unit rate, we need to divide 6 by 51.

51/6 = 8.50

Kevin earns $8.50 per hour

Have a nice day
8 0
3 years ago
Marni recorded the cost of different weights of apples and made a scatter plot of her data!
Alla [95]

Given:

The scatter plot and trend line.

To find:

Type of association, slope, equation of trend line and average cost of apple per pound.

Solution:

Form the given graph it is clear that the trend line passes through the two points (0,0) and (12,24).

Slope of trend line is

m=\dfrac{24-0}{12-0}

m=\dfrac{24}{12}

m=2

Slope of trend line is positive. It means, it represents positive correlation.

So, the type of association of the scatter plot is positive association.

Therefore, the slope of trend line is 2.

The trend line passes through (0,0) have slope 2, so the equation of the trend line is

y-y_1=m(x-x_1)

y-0=2(x-0)

y=2x

Therefore, the equation of trend line is y=2x.

Slope of the line is 2.

Therefore, the average cost of apples per pound is $2.

4 0
3 years ago
Can someone please help with both I would really appreciate it!!!
Viktor [21]

Answer:

slope 2 y intercept 2

slope -1 y intercept 3

Step-by-step explanation:

i would recommend using desmos! it really helps

8 0
4 years ago
Two angles are complementary.
Softa [21]

Answer:

45

Step-by-step explanation:

4 0
3 years ago
Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the pop
Andreyy89

Answer:

The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

Step-by-step explanation:

The complete question is:

The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.

Solution:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 90% confidence level is:

<em>z</em> = 1.645

Compute the required sample size as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\cdot\sigma}{MOE}]^{2}\\\\=[\frac{1.645\times 2103}{500}]^{2}\\\\=47.8707620769\\\\\approx 48

Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

3 0
3 years ago
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