3 years ago

Suppose that Y and Z are points on a number line if YZ=20 and Y lies at 3 where could Z be located

1 answer:

5 0

17? probably I think

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Marizza181 [45]

With some simple rearrangement, we can rewrite the numerator as

$2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1$

Then factorizing the difference of squares, $x^2-1=(x-1)(x+1)$ , we end up with

$\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}$

3 0

2 years ago

steposvetlana [31]

The answer is -6x^2 + 7x, or answer choice A.

6 0

3 years ago

Tresset [83]

Answer:

32.6

Step-by-step explanation:

Look at the decimal in the hundredths place in 32.62

If the number is 0-4, round down. If the number is 5-9, round up.

In 32.62, the number in the hundredths place is 2. So, we round down to 32.6

3 0

2 years ago

natali 33 [55]

The difference would be 0.27

5 0

3 years ago

Hatshy [7]

D would be the correct answer. Post brainliest if this helped plz :)

6 0

3 years ago