Hello.
To find the unit rate, we need to divide 6 by 51.
51/6 = 8.50
Kevin earns $8.50 per hour
Have a nice day
Given:
The scatter plot and trend line.
To find:
Type of association, slope, equation of trend line and average cost of apple per pound.
Solution:
Form the given graph it is clear that the trend line passes through the two points (0,0) and (12,24).
Slope of trend line is



Slope of trend line is positive. It means, it represents positive correlation.
So, the type of association of the scatter plot is positive association.
Therefore, the slope of trend line is 2.
The trend line passes through (0,0) have slope 2, so the equation of the trend line is



Therefore, the equation of trend line is
.
Slope of the line is 2.
Therefore, the average cost of apples per pound is $2.
Answer:
slope 2 y intercept 2
slope -1 y intercept 3
Step-by-step explanation:
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Answer:
45
Step-by-step explanation:
Answer:
The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.
Step-by-step explanation:
The complete question is:
The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.
Solution:
The (1 - <em>α</em>)% confidence interval for population mean is:

The margin of error for this interval is:

The critical value of <em>z</em> for 90% confidence level is:
<em>z</em> = 1.645
Compute the required sample size as follows:

![n=[\frac{z_{\alpha/2}\cdot\sigma}{MOE}]^{2}\\\\=[\frac{1.645\times 2103}{500}]^{2}\\\\=47.8707620769\\\\\approx 48](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ccdot%5Csigma%7D%7BMOE%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D%5B%5Cfrac%7B1.645%5Ctimes%202103%7D%7B500%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D47.8707620769%5C%5C%5C%5C%5Capprox%2048)
Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.