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dimaraw [331]
3 years ago
5

If c cars can be parked in each of the four main rows of the parking lot, what is the expression gor the maximum number of cars

that can be parked in the parking lot?
Mathematics
1 answer:
HACTEHA [7]3 years ago
6 0

Answer:

4c

Step-by-step explanation:

We can say that the maximum number of cars can be represented as:

Maximum number of cars = Total of rows × Number of cars per row

In this particular case, we have 4 rows and the number of cars per row is c, thus, the expression above becomes:

Maximum number of cars = 4c

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This recipe makes 7 portions of chocolate mousse.
Artist 52 [7]

Answer

<h2>hey..! </h2>

She would have to use 2700g chocolate, 150g eggs, 300ml lemon juice and 750 g of sugar.. to make 21 potions

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5 0
3 years ago
If the initial population of panda was 100 and grew to 125 after the first year, which of the following functions best models th
Mumz [18]

Hi,  

if growth continue to the same rate, meaning  +25% more every year, then   B is the answer :

100 (1.25)^t

3 0
4 years ago
The article What is i* if I =o
AnnZ [28]

questions:you have been offered a scholarships to further your studies in Australia

write a diary entry sharing your experience about it

3 0
2 years ago
According to a recent​ survey, the population distribution of number of years of education for​ self-employed individuals in a c
strojnjashka [21]

Answer:

a) n=100,\,\mu_s = 14.7, \,\sigma_s=0.32

b) n=400,\,\mu_s = 14.7, \,\sigma_s=0.16

c) "a.The mean of the sampling distribution stays the same, but the standard error decreases."

Step-by-step explanation:

a) We have a population with mean of 14.7 and standard deviation of 3.2.

We have to calculate the parameters of the sampling distribution (mean and standard deviation), for a sample size of n=100.

The mean for the sampling distribution is the same of the population:

\mu_s=\mu=14.7

The standard deviation of the sampling distribution is related to the population standard deviation by the inverse of the square of the sample size:

\sigma_s=\sigma/\sqrt{n}=3.2/\sqrt{100}=3.2/10=0.32

b) For a sample size of n=400, the mean is the same (14.7), but the standard deviation becomes:

\sigma_s=\sigma/\sqrt{n}=3.2/\sqrt{400}=3.2/20=0.16

c) "a.The mean of the sampling distribution stays the same, but the standard error decreases."

As we calculated, the standard error decreases as the sample size increases. This is because the variability of the variable is reduced as the sample size is bigger.

The mean stays the same independently of the sample size.

7 0
3 years ago
Please I could have some help on this question :)
Mashutka [201]

Answer:

1/5

Step-by-step explanation:

That little weird backwards E covers all the elements within the box in the diagram. There are x(x - 2) paintings from the 20th century, 2x + 8 British paintings, x paintings that are both British and come from the 29th century, and 10 that are neither of these. These should all add up to 60:

x(x - 2) + (2x + 8) + x + 10 = 60

x² - 2x + 3x + 18 = 60

x² + x - 42 = 0

(x + 7)(x - 6) = 0

x = -7 or x = 6

Obviously, we can’t have a negative number of paintings, so x = 6.

Out of the paintings, we choose one that is from the 20th century, and there are:

x + x(x - 2) = 6 + 6 * (6 - 2) = 6 + 24 = 30 paintings from the 20th century

x of these are also British, so since x = 6, the probability we’re looking for is:

6/30 = 1/5

The answer is 1/5.

3 0
3 years ago
Read 2 more answers
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