Hey there! I'm happy to help!
The percent in the problem is 60% (as it has a percent time).
The base is the number we start with, so it is 485.
The amount is the percent of the base. As a decimal, 60% is 0.6. So, we just multiply this by 485.
0.6×485=291
Therefore, the amount is 291.
AMOUNT: 291
BASE: 485
PERCENT: 60%
Have a wonderful day! :D
Answer:
B because they are the same angle
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.
Answer:
12
Step-by-step explanation:
15 - 3 = 12