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Softa [21]
3 years ago
8

Shawn drew a rectangle that was 2 units wide and 6 units long. Draw a different rectangle that has the same perimeter area.

Mathematics
1 answer:
Nitella [24]3 years ago
6 0

Answer:

A square that has sides of 4.5 units, or a rectangle that is 1 unit wide and 8 units long.

Step-by-step explanation:

First, you need to find the perimeter in the first place. Since there are two sides of the same number, you would double each number.

2 would become 4

6 would become 12

Add 4+12=18

So, our rectangle has to have a perimeter of 18 units. Because a square is a rectangle, you can divide 18 and 4, since a square has 4 sides. You get 4.5. Each side can be 4.5 units.

Or, you can have a rectangle. What I thought first was a length of 9, but I knew that wouldn't work. I drew a rectangle and tried 8. If I put it on the top and bottom, which you need to to find the perimeter, it was only 16. Then I knew I could use 1 as a side length. If you added the sides, it would equal 2, and when you add 16 and 2, it's 18. So, you can use a rectangle that has a length of 8 units and a width of 1 unit.

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-4(x+5)=-4x-30 solution
luda_lava [24]

Answer:

no solution

Step-by-step explanation:

-4(x+5)=-4x-30

-4x-20=-4x+30

no solution

x cancel

7 0
3 years ago
Find the area of the parallelogram that has a base of 4m and a height of 5.5m.
Sveta_85 [38]

Answer:

22m²

Step-by-step explanation:

Area of parallelogram is simply the base length x height.

In this case, base length = 4m and height = 5.5m

hence,

Area = 4 x 5.5 = 22m²

3 0
3 years ago
Read 2 more answers
At a collage bookstore Clara purchased a math textbook and a novel that cost a total of $54 not including tax if the price of th
diamong [38]

Answer:

m+n=54 and m=3n+8 is the system of equations that could be used to determine the price of each book.

Step-by-step explanation:

Given,

Total cost of maths book and novel = $54

Let,

Cost of maths book = m

Cost of novel = n

According to given statement;

m+n=54      Eqn 1

the price of the math textbook, m, is $8 more than 3 times the price of the novel

m = 3n+8     Eqn 2

m+n=54 and m=3n+8 is the system of equations that could be used to determine the price of each book.

Step-by-step explanation:

3 0
3 years ago
Which number has an 8 that is 1 tenth the value of the 8 in 78
yKpoI14uk [10]
9.75 i think I’m not really sure do you have any options?
8 0
3 years ago
Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e.
prohojiy [21]

Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

8 0
3 years ago
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