All categories

3 years ago

The solution of a system of linear equations is where the two lines intersect....

Mathematics

2 answers:

azamat3 years ago

6 0

Answer:

Step-by-step explanation:

True.

There is only 1 intersection point. That is the point where the x and y values are the same for both equations. For example if you have

y = 2x + 5 and

y = 3x + 2

The intersect point is (3,11). If you put 3 in each equation for x, they will return 11 for the y value.

I've included a graph to show you that this is true.

olchik [2.2K]3 years ago

5 0

Answer:

True

Step-by-step explanation:

The place where lines intersect is where the x and y values match up.

Just like this, if the lines do not intersect, there's no solution.

If the lines seem to be one line, there is all real number solutions.

Hope this helped!

You might be interested in

Multiplying a trinomial by a trinomial follows the same steps as multiplying a binomial by a trinomial. Determine the degree and

Veseljchak [2.6K]

Degree = 4

Maximum possible number of terms for = 5

Solution:

Given expression:

$\left(x^{2}+x+2\right)\left(x^{2}-2 x+3\right)$

To multiply the trinomial by a trinomial:

$\left(x^{2}+x+2\right)\left(x^{2}-2 x+3\right)$

Multiply each of the first term by the each of the second term.

$=x^{2}(x^{2}-2 x+3)+x(x^{2}-2 x+3)+2(x^{2}-2 x+3)$

$=(x^{4}-2 x^3+3x^2)+(x^{3}-2 x^2+3x)+(2x^{2}-4 x+6)$

Remove the brackets and arrange the terms with same powers together.

$=x^{4}-2 x^3+x^{3}+3x^2-2 x^2+2x^{2}+3x-4 x+6$

$=x^{4}- x^3+3x^2- x+6$

The product of the trinomials is $x^{4}- x^3+3x^2- x+6$ .

Degree is the highest power of the variable.

Degree = 4

Maximum possible number of terms for = 5

3 0

3 years ago

Read 2 more answers

1,298.713832<br>+2.475,147,963

ddd [48]

Answer:

1412.188832

Step-by-step explanation:

6 0

3 years ago

7.89x10^-6+2.35x10^-8

RSB [31]

$7.89 \times {10}^{ - 6} + 2.35 \times {10}^{ - 8} = 7.9135 \times {10}^{ - 6}$

5 0

3 years ago

Read 2 more answers

Suppose a triangle has sides a, b, and c let theta be the angle opposite the side of length a. If cos theta < 0 what must be

LenaWriter [7]

Using the cosine rule, a² = b² + c² -2 bc cos θSImplifying the equation in terms of cos theta,
cos(θ) = (a² + c² - b²)/(2bc)
(a² + c² - b²)/(2bc) > 0 a² + c² - b² > 0
assuming b and c are non zeros, the resulting inequality should be
a² + c² > b²

THe appicable inequality is a

4 0

3 years ago

Read 2 more answers

Can you please answer this quickly, i will give you a lot of points.

Rudiy27

The first one is 10^-5 and the second one is 10^5.

8 0

4 years ago

Read 2 more answers