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icang [17]
3 years ago
8

Couldn’t find correct answer if you know please help

Mathematics
1 answer:
Gnoma [55]3 years ago
8 0

<em>Answer</em><em>:</em>

the answer to your question is 3

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Micah mixed 3 ounces of yellow paint with 5 ounces of blue paint. What is the ratio of blue paint to the total amount of paint t
kaheart [24]
5:8
3+5=
8 (all ounces added)
5(ounces of blue)

6 0
3 years ago
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The probability of a certain plant growing taller than 4 meters is 1/3. If I plant 2 of these plants, find the probability that
lana [24]
\frac{1}{3}^2\\\frac{1}{3}*\frac{1}{3}\\\frac{1}{9}

1 / 9
5 0
3 years ago
A food manufacturer uses an extruder (a machine that makes bite size cookies)that yields revenue for the firm at a rate of $200
julsineya [31]

Answer:

$1300

Step-by-step explanation:

The extruder yields a revenue of $200per hour

Y denotes the number of breakdown per day.

The daily revenue generated is given as

R = 1600 - 50Y^2

We have an average of 2 breakdown per day

Lamda = 2

Represent lamda as β

E(Y) = β

E(Y(Y-1)) = β^2

E(Y^2) = E[Y(Y-1)] + E(Y)

= β^2 + β

E(R) = E(1600 - 50Y^2)

= 1600 - 50E(Y^2)

= 1600 - 50(β^2 +β)

Recall that β = lamda = 2

= 1600 - 50(2^2 + 2)

= 1600 - 50(4+2)

= 1600 - 50(6)

= 1600 - 300

= 1300

$1300

The expected daily revenue of the extruder is $1300

3 0
3 years ago
Suppose that x is a binomial random variable with n=5, p=. 3,and q=. 7.1. Write the binomial formula for this situation and list
Radda [10]

Answer:

P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}

Possible values of x: Any from 0 to 5.

P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807

P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015

P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087

P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323

P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835

P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this question:

n = 5, p = 0.3, q = 1 - p = 0.7

So

P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}

Possible values of x: 5 trials, so any value from 0 to 5.

For each value of x calculate p(☓ =x)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807

P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015

P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087

P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323

P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835

P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243

8 0
3 years ago
What equation can you write to solve for x?
KengaRu [80]

Answer:

(3x) ° + (x+ 10)° = 90°

Step-by-step explanation:

(3x) ° + (x+ 10)° = 90°

3x + x + 10 = 90

4x = 90 - 10

4x = 80

x = 20

(3x) ° = 3 x 20 = 60°

(x + 10)° = 20 + 10 = 30°

4 0
3 years ago
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