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DaniilM [7]
2 years ago
10

Which of these are NOT potential rational roots of 8x^3 + 15x^2 – 7x – 5?

Mathematics
1 answer:
VashaNatasha [74]2 years ago
5 0

The numbers that are not potential rational roots of the polynomial function, are numbers other than any of \pm 1, \pm \frac 12,\pm \frac 14,\pm \frac 18,\pm 5, \pm \frac 52, \pm \frac 54, \pm \frac 58

The polynomial function is given as:

g(x) = 8x^3 + 15x^2 - 7x -5

<h3>How to calculate the potential rational roots</h3>

The potential rational roots of a polynomial function g(x).

Such that: g(x) = px^n + ....+q

is:

Roots = \pm \frac{Factors\ of\ q}{Factors\ of\ p}

So, we start by listing out the factors of 5 and 8

5 =1 ,5

8 =1 ,2,4,8

Roots = \pm \frac{Factors\ of\ q}{Factors\ of\ p} becomes

Roots = \pm \frac{1,5}{1,2,4,8}

Simplify

Roots = \pm 1, \pm \frac 12,\pm \frac 14,\pm \frac 18,\pm 5, \pm \frac 52, \pm \frac 54, \pm \frac 58

Hence, the numbers that are not potential rational roots of the polynomial function, are numbers other than any of \pm 1, \pm \frac 12,\pm \frac 14,\pm \frac 18,\pm 5, \pm \frac 52, \pm \frac 54, \pm \frac 58

Read more about potential rational roots at:

brainly.com/question/7594092

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weqwewe [10]

Let...

1st number=x

2nd number=x+2

3rd number=x+4

4th number=x+6

x+x+2+x+4+x+6=200

4x=188

x=47

x+6=53

answer: 53

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Answer:

the total amount is £756.

Step-by-step explanation:

given, monthly charge =£16

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rate per texts= £15per text (150 free text)

now, total calls made =170calls

total text = 180 text

now, minimum charge for 150 calls is free

so, left calls = 20 calls

charge for 20 calls= 20×£13

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now, total amount = monthly charge + extra call charge+ extra text charge.

or, total amount = £16+£260+£480

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How many 1/5 inch pieces can be cut from a sting 8 inches long
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Another method :

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Factor the expression completely.
evablogger [386]

Answer:

Factoring the expression xy^4+x^4y^4 completely we get \mathbf{xy^4(x+1)(x^2-x+1)}

Step-by-step explanation:

We need to factor the expression xy^4+x^4y^4 completely

We need to find common terms in the expression.

Looking at the expression, we get xy^4 is common in both terms, so we can write:

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So, taking out the common expression we get: xy^4(1+x^3)

Now, we can factor the term (1+x^3) or we can write (x^3+1) by using formula:

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So, we get:

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Therefor factoring the expression xy^4+x^4y^4 completely we get \mathbf{xy^4(x+1)(x^2-x+1)}

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