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Marina86 [1]
3 years ago
13

Solve for m in the following equation: x = -2kn + m)

Mathematics
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

The answer is m = x + 2kn

Step-by-step explanation:

Rewrite the equation as  − 2 k n  +  m  =  x . Add  2 k n  to both sides of the equation.

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Nonamiya [84]

Its 13 cause 26 times.5 is 13

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2 years ago
Write an equivalent expression to x-9y+ 4.
Paul [167]
D. x - 9y + 4 = x + 4 + (-9y)
7 0
2 years ago
I need help on this guys pls help me
STatiana [176]

Answer:

The answer is A

Step-by-step explanation:

The reason A is correct is because all of the other transformations change the size of the triangle, and A is the only answer that only reflects the image over the y axis without changing it, thus making it similar to the preimage

4 0
2 years ago
17c-10=4 ............................
Katarina [22]

Answer:

1.214 or 1\frac{3}{14} or \frac{17}{14}

Step-by-step explanation:

To solve this equation, first you need to the variable term isolated. You do this by adding 10 to each side. Your equation will now look like

17c = 14

Next, you will divide both sides by the 17.

Your equation now is solved, and above, I put ther three different forms for your answer: decimal, mixed number, and improper fraction.

~theLocoCoco

7 0
3 years ago
I Need to find the Function Operations​
Alinara [238K]

Answer:

1) (f+g)(x)=2x^2+3x-6

2) (f-g)(x)=2x^2+x

3) (f \cdot g)(x)=2x^3-4x^2-9x+9

Step-by-step explanation:

So we have the two functions:

f(x)=2x^2+2x-3\text{ and } g(x)=x-3

And we want to find (f+g)(x), (f-g)(x), and (f*g)(x).

1)

(f+g)(x) is the same to f(x)+g(x). Substitute:

(f+g)(x)=f(x)+g(x)\\=(2x^2+2x-3)+(x-3)

Combine like terms:

=(2x^2)+(2x+x)+(-3-3)

Add:

=2x^2+3x-6

So:

(f+g)(x)=2x^2+3x-6

2)

(f-g)(x) is the same to f(x)-g(x). So:

(f-g)(x)=f(x)-g(x)\\=(2x^2+2x-3)-(x-3)

Distribute:

=(2x^2+2x-3)+(-x+3)

Combine like terms:

=(2x^2)+(2x-x)+(-3+3)

Simplify:

=2x^2+x

So:

(f-g)(x)=2x^2+x

3)

(f*g)(x) is the same to f(x)*g(x). Thus:

(f\cdot g)(x)=f(x)\cdot g(x)\\=(2x^2+2x-3)(x-3)

Distribute:

=(2x^2+2x-3)(x)+(2x^2+2x-3)(-3)

Distribute:

=(2x^3+2x^2-3x)+(-6x^2-6x+9)

Combine like terms:

=(2x^3)+(2x^2-6x^2)+(-3x-6x)+(9)

Simplify:

=2x^3-4x^2-9x+9

So:

(f \cdot g)(x)=2x^3-4x^2-9x+9

4 0
3 years ago
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