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3 years ago

Your EZ Pass account begins with $80. It costs you $4/day. Write an equation

Mathematics

1 answer:

vivado [14]3 years ago

7 0

Answer:

The equation is $A(d) = 80 - 4d$

Step-by-step explanation:

Linear function:

A linear function for the amount of money in an account after t days is given by:

$A(d) = A(0) - md$

In which A(0) is the initial value and m is the daily cost.

Your EZ Pass account begins with $80. It costs you $4/day.

This means that $A(0) = 80, m = 4$

$A(d) = A(0) - md$

$A(d) = 80 - 4d$

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1\4 fractions division

scoundrel [369]

Not sure what the question is
But 1/4 as a decimal gives us 0.25

4 0

3 years ago

Suppose that during one period extreme cold,the average daily temperature decreased 1 1/2 F each day. How many days did it take

Alenkasestr [34]

We have been given that during one period extreme cold, the average daily temperature decreased $1\frac{1}{2}$ degree F each day. We are asked to find number of days it will take for the temperature to decrease by 9 degree F.

First of all we will convert our mixed fraction into improper fraction.

$1\frac{1}{2}=\frac{3}{2}$

Now we will divide total temperature change (9) by average daily temperature change ( $\frac{3}{2}$ ) to find number of days.

$9\div\frac{3}{2}$

Dividing a number by a fraction is same as multiplying the number by reciprocal of the fraction.

$9\cdot\frac{2}{3}$

$3\cdot2=6$

Therefore, it will take 6 days for the temperature to decrease by 9 degree F.

7 0

3 years ago

Determine whether there is a difference between the two data sets that is not apparent from a comparison of the measures of cent

Iteru [2.4K]

Answer:

It seems the question is incomplete as the two data sets implied from the question are not visible.

However, two data sets having identical measures of center have a difference.

Step-by-step explanation:

Let's consider these two data sets:

2, 2, 3, 5, 6, 6 and 1, 1, 1, 1, 1, 19

Both were contrived.

The most reliable among the measures of center is the mean. The mean of each is calculated by summing the data and dividing by the number of elements. In both sets, the mean is 4.

The data in the first set seem to be concentrated around the mean indeed. But for the second data set, one of them, 19, is obviously very far from the others and the mean. We need another measure to describe this: standard deviation.

Its formula is:

$\rho=\sqrt{\dfrac{\sum (x-\overline{x})^2}{n}}$

$x$ represents each data, $\overline{x}$ is the mean and $n$ is the number of items. $x-\overline{x}$ is the deviation from the mean of each data item.