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3 years ago

Raju is cycling at a speed of 30km/h. He applies brakes and stops at a junction in 10s. Calculate the acceleration.

Mathematics

1 answer:

Sedbober [7]3 years ago

7 0

Answer:

Acceleration = 3m/s²

Step-by-step explanation:

Here ,

Initial velocity = 30km/h

Final velocity = 0km/h

Time = 10s

Acceleration = ?

We know ,

A = v-u/t

or , A = 0-30/10

or, A = 30/10

A = 3m/s²

Therefore the acceleration is 3m/s²

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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Step-by-step explanation:

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3 years ago

You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the

natita [175]

Answer:

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$4,000$ at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

First account

$t=1 years\\ P=\$x\\ r=0.03$

substitute in the formula above

$I=x(0.03*1)$

$I=0.03x$

Second account

$t=1 years\\ P=\$(7,000-x)\\ r=0.05$

substitute in the formula above

$I=(7,000-x)(0.05*1)$

$I=350-0.05x$

Remember that

The interest is equal to $\$290$

Adds the interest of both accounts

$0.03x+350-0.05x=\$290$

$0.05x-0.03x=350-290$

$0.02x=60$

$x=\$3,000$

therefore

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In the second account was invested $\$7,000-\$3,000=\$4,000$ at 5%

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3 years ago

Question

Alekssandra [29.7K]

Answer:

$d=7.8\ g/cm^3$

Step-by-step explanation:

Given that,

The dimensions of a rectangular block = 4 cm x 2 cm x 1.5 cm

Mass, m = 93.6 g

We need to find the density of steel. We know that the density of an object is equal to the mass divided by volume. So,

$d=\dfrac{m}{V}\\\\d=\dfrac{93.6}{4\times 2\times 1.5}\\\\d=7.8\ g/cm^3$

So, the density of the steel is $7.8\ g/cm^3$ .

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3 years ago