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4 years ago

What is -8.3 - (-5.4)

Mathematics

2 answers:

Vera_Pavlovna [14]4 years ago

8 0

Answer:

Step-by-step explanation:

-11.7

A negative and a a negative will be added together

Anna007 [38]4 years ago

4 0

Answer:

$-2.9$

Step-by-step explanation:

$-8.3--5.4$

The 2 negatives cancel out and make a positive:

$-8.3+5.4$

$-2.9$

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Jackie spent the same amount of money on cassette tapes and compact discs. If tapes cost $12 and CDs cost $16, what is the least

11Alexandr11 [23.1K]

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the least is $24 or $26

Step-by-step explanation:

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3 years ago

Convert: 6y + y² = x² from rectangular to polar form.

11Alexandr11 [23.1K]

$\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\\\
cos(2\theta)=
\begin{cases}
\boxed{cos^2(\theta)-sin^2(\theta)}\\
1-2sin^2(\theta)\\
2cos^2(\theta)-1
\end{cases}\\\\\\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-------------------------------\\\\$

$\bf 6y+y^2=x^2\implies \cfrac{6y}{x^2}+\cfrac{y^2}{x^2}=1\implies \cfrac{6rsin(\theta )}{[rcos(\theta )]^2}+\cfrac{[rsin(\theta )]^2}{[rcos(\theta )]^2}=1
\\\\\\
\cfrac{6rsin(\theta )}{r^2cos^2(\theta )}+\cfrac{r^2sin^2(\theta )}{r^2cos^2(\theta )}=1\implies 
\cfrac{6sin(\theta )}{rcos^2(\theta )}+\cfrac{sin^2(\theta )}{cos^2(\theta )}=1$

$\bf \cfrac{6sin(\theta )}{rcos^2(\theta )}=1-\cfrac{sin^2(\theta )}{cos^2(\theta )}\implies \cfrac{6sin(\theta )}{1-\frac{sin^2(\theta )}{cos^2(\theta )}}=rcos^2(\theta )
\\\\\\
\cfrac{6sin(\theta )}{cos^2(\theta )\left[ 1-\frac{sin^2(\theta )}{cos^2(\theta )} \right]}=r\implies \cfrac{6sin(\theta )}{cos^2(\theta )-sin^2(\theta )}=r
\\\\\\
\cfrac{6sin(\theta )}{cos(2\theta )}=r$

5 0

3 years ago

I HAVE 10 MIN PLZ HELP

Sedbober [7]

Answer: The awnser is 16 weeks

Step-by-step explanation: this is the awnser because 12.50 x 16 is $200 and if does 17 weeks it will be $212.50

7 0

3 years ago

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I need help in these questions

Salsk061 [2.6K]

Answer:

see explanation

Step-by-step explanation:

All of these questions use the external angle theorem, that is

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠3 = 43° + 22° = 65°

∠2 + 71 = 92 ( subtract 71 from both sides )

∠2 = 21°

90 + ∠4 = 123 ( subtract 90 from both sides )

∠4 = 33°

2x - 15 + x - 5 = 148

3x - 20 = 148 ( add 20 to both sides )

3x = 168 ( divide both sides by 3 )

x = 56

Hence ∠ABC = x - 5 = 56 - 5 = 51°

2x + 27 + 2x - 11 = 100

4x + 16 = 100 ( subtract 16 from both sides )

4x = 84 ( divide both sides by 4 )

x = 21

Hence ∠JKL = 2x - 11 = (2 × 21) - 11 = 42 - 11 = 31°

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4 years ago

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Alenkinab [10]

Answer:

Step-by-step explanation:

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3 years ago

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