Answer:
(Y∩Z)∩X = {r,a,e}
Step-by-step explanation:
U = {a,b,c,d,e,f,............,z)
X = { t,r,i,a,n,g,l,e}
Y = {t,r,a,p,e,z,o,i,d}
Z = {h,y,p,e,r,b,o,l,a}
Firstly,
Y∩Z = {t,r,a,p,e,z,o,i,d} ∩ {h,y,p,e,r,b,o,l,a} [<u><em>Intersection : Common Elements</em></u>]
=> Y∩Z = {r,a,p,e,o}
Now,
(Y∩Z)∩X = {r,a,p,e,o} ∩ { t,r,i,a,n,g,l,e}
=> (Y∩Z)∩X = {r,a,e}
