All categories

2 years ago

PLEASE HELP ASAP 25 POINTS

Mathematics

1 answer:

motikmotik2 years ago

6 0

Answer:

it's b

Step-by-step explanation:

If you can use your phone in class, I highly suggest the desmos app because you can just put the equations in and it shows you everything

You might be interested in

David made $80,950 last year. If his income is decreased by 7.25%, what is his adjusted

Taya2010 [7]

Answer:

75081

Step-by-step explanation: multiply 80950 by 0.9275

5 0

2 years ago

Bill earns $87.50 per week and Jack earns $70.00 per week. What percent of Bill's salary is Jack's?

skelet666 [1.2K]

I believe it is 80%. Hope that helped.

8 0

3 years ago

Read 2 more answers

Please show work for questions 6 and 14

maxonik [38]

Actually I had learnt this but.....do u want a formula ?

6 0

2 years ago

A right cone has radius 9cm and slant height 12cm. The radius and slant height are both multiplied by 2/3. Which of the followin

Olegator [25]

Answer:

<em>The surface area is multiplied by 4/9.</em>

Step-by-step explanation:

<u>Surface Area of a Cone</u>

Being r the radius and l the slant height of a cone, then its surface area is

$SA=\pi r^2+\pi r l$

Now let's think both the radius and the slant height are multiplied by the same factor k, i.e.

r'=kr

l'=kl

The new surface area is

$SA'=\pi r'^2+\pi r' l'=\pi (kr)^2+\pi \cdot kr\cdot kl=k^2\pi r^2+k^2\pi rl$

$SA'=k^2(\pi r^2+\pi rl)=k^2\cdot SA$

The new surface area is the $k ^2$ times original SA. Since k=2/3, then

$SA'=4/9\ SA$

The surface area is multiplied by 4/9.

6 0

2 years ago

Inveres laplace transform (3s-14)/s^2-4s+8

Olenka [21]

Complete the square in the denominator.

$s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4$

Rewrite the given transform as

$\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}$

Now take the inverse transform:

$L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}$

5 0

2 years ago