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4 years ago

6-3(x-5)=5x-11 how do i do this

Mathematics

2 answers:

nasty-shy [4]4 years ago

8 0

Expand

6 - 3x + 15 = 5x - 11

Simplify 6 - 3x + 15 to -3x + 21

-3x + 21 = 5x - 11

Add 3x to both sides

21 = 5x - 11 + 3x

Simplify 5x - 11 + 3x to 8x - 11

21 = 8x - 11

Add 11 to both sides

21 + 11 = 8x

Simplify 21 + 11 to 32

32 = 8x

Divide both sides by 8

32/8 = x

Simplify 32/8 to 4

4 = x

Switch sides

x = 4

Jet001 [13]4 years ago

4 0

Answer:

4=x

Step-by-step explanation:

6-3(x-5)=5x-11

Distribute the -3

6 -3x +15 = 5x -11

Combine like terms

21 -3x = 5x-11

Add 3x to each side

21-3x+3x = 5x+3x-11

21 = 8x-11

Add 11 to each side

21+11 = 8x-11+11

32 = 8x

Divide by 8

32/8 = 8x/8

4 =x

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Read 2 more answers

Part A: Plot the points A(-8,7) and B(6,-9). Mark the halfway point on AB and label it point M. What are the coordinates of M? P

vredina [299]

Answer:

a. $M(x,y) = (-1,-1)$

b. $D(-4,-9)$

Step-by-step explanation:

Given

A(-8,7) and B(6,-9).

Solving (a):

Determine the Midpoint M;

This is calculated as follows;

$M(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Where

$(x_1,y_1) = (-8,7)$

$(x_2,y_2) = (6,-9)$

Substitute these values in the formula

$M(x,y) = (\frac{-8+6}{2},\frac{7-9}{2})$

$M(x,y) = (\frac{-2}{2},\frac{-2}{2})$

$M(x,y) = (-1,-1)$

Hence; the midpoint is (-1,-1)

Solving (a):

Here, we have

C = (2,7)

M; Midpoint = (-1,-1)

Required: Determine D

This is calculated as follows;

$M(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Where

$(x_1,y_1) = (2,7)$

$(x,y) = (-1,-1)$

Substitute these values in the formula

$(-1,-1) = (\frac{2+x_2}{2},\frac{7+y_2}{2})$

Solving for x2

$-1 = \frac{2 + x_2}{2}$

Multiply both sides by 2

$-2 = 2 + x_2$

Subtract 2 from both sides

$x_2 = -2 - 2$

$x_2 = -4$

Solving for y2

$-1 = \frac{7 + y_2}{2}$

Multiply both sides by 2

$-2 = 7 + y_2$

Subtract 7 from both sides

$y_2 = -2 - 7$

$y_2 = -9$

Hence, the coordinates of D is

$D(-4,-9)$

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