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2 years ago

Solve the equation by factoring: x^2 - 5x = 14

Mathematics

1 answer:

daser333 [38]2 years ago

7 0

Answer:

x=7, x= -2

Step-by-step explanation:

Start by putting the whole equation to one side: x2-5x=14 ----> x2-5x-14=0
Next, factor the equation: x,x -7,2 ----> (x-7)(x+2)=0
Now, solve both equations: x-7=0....x=7 AND x+2=0.....x= -2
Plug both in to make sure that they are correct....both are correct

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Answer:

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center = 5, -1

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

If 3 is added to twice a number the result is 17 find the number

Sergeu [11.5K]

For this, the number we are looking for is x.

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3 years ago

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Select the correct answer

lora16 [44]

Answer:

Data set 3 has the highest IQR, so the correct option is {13,17,12,21, 18,20}

Step-by-step explanation:

The question is:

Which data set has the greatest spread for the middle 50% of its data

We have given the data sets:

{18,13,22, 17, 21, 24}

{17,19,22,26,17,14}

{13,17,12,21, 18,20}

{18,21,16,22,24,15}

To find the greatest spread for the middle we need to find the IQR for all the data sets and check which one is highest.

So,

For the first set: 22-17 = 5

For the second: 22-17 = 5

For the third set = 20-13 = 7

For the fourth set = 22-16 = 6

Since data set 3 has the highest IQR, so the correct option is {13,17,12,21, 18,20} ....

8 0

2 years ago

You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample

Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=160)$

And the distribution for $\bar X$ is:

$\bar X \sim N(\mu, \frac{160}{\sqrt{n}})$

We know that the margin of error for a confidence interval is given by:

$Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The next step would be find the value of $\z_{\alpha/2}$ , $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$

Using the normal standard table, excel or a calculator we see that:

$z_{\alpha/2}=\pm 1.96$

If we solve for n from formula (1) we got:

$\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}$

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And we have everything to replace into the formula:

$n=(\frac{1.96(160)}{78.4})^2 =16$

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And now we can replace the new value of Me and see what we got, like this:

$n=(\frac{1.96*160}{60})^2 =27.32$

And if we round up the answer we see that the value of n to ensure the margin of error required $Me=\pm 60$ $ is n=28.

5 0

2 years ago