Well, since 3/15 can be simplified to 1/5 by dividing the top and the bottom by 3, you would just need to find the decimal of 1/5 which is much more commonly recognized. it's .2 (becasue 1/10 would be .1 and 1/5=2/10 so .1x2=.2)
Answer: (4,3)
Step-by-step explanation:
1. In this method you must solve one of the equation for one of the variables and substitute it into the other equation to find the other variable. Then, substitute the value of that variable into one of the original equation to obtain the value of the other one.
2 You have that:
3. Then, you can substitute it into the other equation and solve for x:
4. Now you can obtain y:
5. The answer is:
(4,3)
Answer:
1. The y-intercept
2. The slope of the equation represent the relationship between the time duration in which Clarissa eats chocolate is 1/10
Step-by-step explanation:
1. The value of the y coordinate at the point which the graph meets the y-axis is called to the y-intercept. It is the value at which the x-coordinate is equal to zero, that is, the coordinate of the point at the y-intercept = (y, 0)
2. Given that Clarissa eats 1 piece of chocolate every 10 seconds, we have the slope of the equation represent the relationship between the time duration in which Clarissa eats chocolate is 1/10.
1.
Domain: {-1, 0, 2, 3}
Range: {2, 4, 6}
2.
Ax+By=C: linear equation standard form
y=mx+b: slope intercept form
(y-y^1)=m(x-x^1): point slope form
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
