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3 years ago

Solve the equation by factoring: x^2 - 5x = 14

Mathematics

1 answer:

daser333 [38]3 years ago

7 0

Answer:

x=7, x= -2

Step-by-step explanation:

Start by putting the whole equation to one side: x2-5x=14 ----> x2-5x-14=0
Next, factor the equation: x,x -7,2 ----> (x-7)(x+2)=0
Now, solve both equations: x-7=0....x=7 AND x+2=0.....x= -2
Plug both in to make sure that they are correct....both are correct

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If A = i +3j -2K and B=4i-2j+4k Find (2A+B).(A-2B)

Marizza181 [45]

GIVEN :

a = 1/√10 ( 3i + k) and

b = 1/7 ( 2i + 3j - 6k)

TO FIND :

( 2a- b) . [ ( a x b ) x ( a + 2b)]

SOLUTION :

◆Going with the equation given,

( 2a - b) . [ ( a x b ) x ( a + 2b)]

= (2a - b) [( a×b×a) + 2(a×b)×b]

◆BAC - CAB RULE,

A×B×C = B( A.B ) - C(A.B )

= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]

Solving further

= (2a - b )(b - 2a)

= -4a.a -b.b

=-5.

Answer:

( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5

Hoped I helped

8 0

3 years ago

Simplifying radicals

Xelga [282]

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$\sqrt{12} - \sqrt{48} =$

$\sqrt{12} - \sqrt{4 \times 12} =$

$\sqrt{4 \times 3} - \sqrt{4 \times 4 \times 3} =$

$\sqrt{ {2}^{2} \times 3 } - \sqrt{ {4}^{2} \times 3 } =$

$2 \sqrt{3} - 4\sqrt{3} =$

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8 0

3 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the zero-product property and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the second equation and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

6 0

1 year ago

Read 2 more answers

Logan bought 15 balloons four-fifths all of the balloons are purple. How many of the balloons are purple? Draw a model to show h

8090 [49]

Separating the balloons into five equal groups

⊙⊙⊙ ___ ⊙⊙⊙ ___ ⊙⊙⊙ ___ ⊙⊙⊙ ___ ⊙⊙⊙ 

each group (fifth) has three balloons ___ four-fifths is twelve

5 0

3 years ago

Can someone explain to me how to do this and give me the answer please?

pantera1 [17]

Answer:

To find x, y, z, p and q, you need to know about the property of Rhombus.

13y + 10 = 7y + 16 (pair of equal opposite sides)

=> 6y = 6

=> y = 1

x = 7x + 16 (2 equal adjacent sides)

= 7*1 + 16

=23

z = 90 deg (angle between 2 diagonals)

q = 22 deg (isosceles triangle)

p = 90 - 22 = 68 deg (right triangle)

4 0

3 years ago