Joshua travelled for 3 hours at the constant speed of 60 mi/h
<h3><u>Solution:</u></h3>
Given that, Joshua traveled 5 hours from City A to City B
The distance between the cities is 260 miles.
First he traveled at the constant speed of 40 mi/h, and then at the constant speed of 60 mi/h.
So, let the number of hours he travelled with 40 mi/h be "n" hours and the distance travelled be "x" miles
Then, the time in which he travelled with 60 mi/h will be 5 – n hours and distance travelled will be 260 – x miles
We have to find how many hours did he travel at the constant speed of 60 mi/h
<em><u>The relation between speed and distance is given as:</u></em>



So, he travelled 2 hours with speed of 40 mi/h and 5 – 2 = 3 hours with speed of 60 mi/h
Hence, he travelled for 3 hours