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3 years ago

6x + 4 = 5x+17 + 120 need this answerd ASAP pls! thank u!

Mathematics

1 answer:

igomit [66]3 years ago

6 0

Answer:

x = 133

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

6x + 4 = 5x + 17 + 120

Step 2: Solve for x

Combine like terms: 6x + 4 = 5x + 137
Isolate x terms: x + 4 = 137
Isolate x: x = 133

Step 3: Check

Plug in x into the original equation to verify it's a solution.

Substitute in x: 6(133) + 4 = 5(133) + 17 + 120
Multiply: 798 + 4 = 665 + 17 + 120
Add: 802 = 682 + 120
Add: 802 = 802

Here we see that 802 does indeed equal 802.

∴ x = 133 is the solution to the equation.

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Ira Lisetskai [31]

Answer:

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Step-by-step explanation:

$\because 52.5 + x = 75\\\therefore x = 75 - 52.5\\\therefore 75 - 52.5 = x \\$

is the correct answer.

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3 years ago

2m+5=5(m-7)-3m equals??

Svetradugi [14.3K]

2m+5=5(m-7)-3m
first, use distributive property...
2m+5=5m-35-3m
next, combine like terms on the right side...
2m+5=2m-35
next, subtract 2m from both sides.
2m+5=2m-35
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you will get....
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3 years ago

Read 2 more answers

4x -2 + 5x +6 What does this equal

egoroff_w [7]

Answer:

9x+4

Step-by-step explanation:

8 0

3 years ago

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What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for n :

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$

$\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6$

5 0

3 years ago

3b-2a Need help on assignment

Bond [772]

Answer: -2a + 3b

Solution:

3b - 2a
Simplify

= -2a + 3b

8 0

2 years ago