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____ [38]
3 years ago
8

Solve for X. y=1/4 (x)+3

Mathematics
1 answer:
tia_tia [17]3 years ago
3 0
The answer is:
____________________
x = 4y - 12 ; (Assuming the problem meant to solve for "x"; "in terms of "y").
_______________________
{Otherwise, the question might be "incomplete".}.
______________________________________________
The question seems incomplete; how can we solve for "x" when we do not know what "y" equals?
__________________________
However, it could be possible to "solve for x" in terms of "y".  To so this, we need to isolate ""x" on one side of the equation:
_______________________________
Given: <span>y=1/4 (x) + 3 ; Let us multiply the ENTIRE EQUATION (both sides) by "4", to get rid of the "1/4" (fraction coefficent) of "x", and to "cancel out" the "1/4" fraction cofficient of "x" to the implied "1"; to help solve for "x" :
________________________________________
4 *{ </span>y= 1/4 (x) + 3} ;
______________________
4y = x + 12 ; Now we can subtract "12" from EACH SIDE of the equation;                       to isolate "x" on one side of the equation; and to solve for "x":
_______________________
4y - 12 = x + 12 - 12 ;
________________________
4y - 12 = x ; This is our answer:
___________________________
x = 4y - 12 ; (Assuming the problem meant to solve for "x"; "in terms of "y").
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Two angles are complementary. The first angle is 2x degrees. The second angle is (3x +5) degrees. Determine the measure of each
bixtya [17]

Answer:

70 and 110

Step-by-step explanation:

First angle -- 2x

Second angle -- 3x + 5

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2x + 3x + 5 = 180

5x = 175

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How to convert base two to base three​
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Consider this example: say we want to convert <em>x</em> = 11 0101 1001₂ to base 3.

The binary expansion of <em>x</em> is

<em>x</em> = 1×2⁹ + 1×2⁸ + 1×2⁶ + 1×2⁴ + 1×2³ + 1×2⁰

which in base 10 reduces to

<em>x</em> = 512 + 256 + 64 + 16 + 8 + 1 = 857

Recall the first several powers of 3:

3⁰ = 1; 3¹ = 3; 3² = 9; 3³ = 27; 3⁴ = 81; 3⁵ = 243; 3⁶ = 729

Now it's a matter of computing quotients and remainders. Pick the largest power of 3 that fits into the target number, then check the remainder and repeat.

• How many times does the 729 go into 857? 1 time, and it leaves a remainder of 128, or

857 = 1×729 + 128 = 1×3⁶ + 128

• How many times does 81 go into 128? Also 1 time, so

128 = 1×81 + 47 = 1×3⁴ + 47

• How many times does 27 go into 47? Also 1 time,

47 = 1×27 + 20 = 1×3³ + 20

• How many times does 9 go into 20? 2 times,

20 = 18 + 2 = 2×9 + 2 = 2×3² + 2

• How many times does 1 go into 2? Also 2 times,

2 = 2 + 1 = 2×1 + 0 = 2×3⁰

So we found

857 = 1×3⁶ + 1×3⁴ + 1×3³ + 2×3² + 2×3⁰

which is the ternary expansion of <em>x</em>,

<em>x</em> = 1 011 202₃

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