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____ [38]
3 years ago
8

Solve for X. y=1/4 (x)+3

Mathematics
1 answer:
tia_tia [17]3 years ago
3 0
The answer is:
____________________
x = 4y - 12 ; (Assuming the problem meant to solve for "x"; "in terms of "y").
_______________________
{Otherwise, the question might be "incomplete".}.
______________________________________________
The question seems incomplete; how can we solve for "x" when we do not know what "y" equals?
__________________________
However, it could be possible to "solve for x" in terms of "y".  To so this, we need to isolate ""x" on one side of the equation:
_______________________________
Given: <span>y=1/4 (x) + 3 ; Let us multiply the ENTIRE EQUATION (both sides) by "4", to get rid of the "1/4" (fraction coefficent) of "x", and to "cancel out" the "1/4" fraction cofficient of "x" to the implied "1"; to help solve for "x" :
________________________________________
4 *{ </span>y= 1/4 (x) + 3} ;
______________________
4y = x + 12 ; Now we can subtract "12" from EACH SIDE of the equation;                       to isolate "x" on one side of the equation; and to solve for "x":
_______________________
4y - 12 = x + 12 - 12 ;
________________________
4y - 12 = x ; This is our answer:
___________________________
x = 4y - 12 ; (Assuming the problem meant to solve for "x"; "in terms of "y").
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EastWind [94]
<span>60 Sorry, but the value of 150 you entered is incorrect. So let's find the correct value. The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So (300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500 So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that: (375+x)(240+x)-90000 = 40500 The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation: (375+x)(240+x)-90000 = 40500 x^2 + 375x + 240x + 90000 - 90000 = 40500 x^2 + 615x = 40500 x^2 + 615x - 40500 = 0 Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
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VashaNatasha [74]
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The surf instructor has an initial fee of $12 and charges $8 per hour for lessons, which is represented by the equation y = 8x +
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If 55% people in a city like Cricket, 30% like Football and the remaining like nother games, then what per cent of the people li
labwork [276]

\large{\dag\:{\underline{\underline{\frak{\pmb{\red{Answer:-}}}}}}}

  • Cricket = 55%
  • Football = 30%
  • Other games = Remaining (?)

So, the percent of people who like <u>other games</u> equals:

= 100 – (55 + 30)

= 100 – 85

= 15%

<u>If </u><u>the </u><u>total </u><u>no.</u><u> </u><u>of.</u><u> </u><u>people</u><u> </u><u>is </u><u>6</u><u>0</u><u>,</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u>:

★ Cricket

= 60,00,000 × 55/100

= 33,00,000

★ Football

= 60,00,000 × 30/100

= 18,00,000

★ Other sports

= 60,00,000 × 15/100

= 9,00,000

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