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2 years ago

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Choose the correct product of (5x − 11)2. 25x2 − 110x 121 25x2 − 121 25x2 121 25x2 110x 121.

1 answer:

chubhunter [2.5K]2 years ago

5 0

Product is the multiplication of numbers. The product of the (5x-11)² is (25x²-110x+121).

<h3>What is a Product?</h3>

A product is the multiplication of a number or expression to another expression.

We know in order to find the product of (5x-11)², we need to multiply each of the terms inside the bracket to each term in the second bracket. therefore, the solution of the problem can be given as,

$(5x-11)^2\\\\= (5x-11) \times (5x-11)\\\\= (5x \times 5x)-(5x \times 11)-(5x \times 11)(11 \times 11)\\\\= 25x^2 - 55x - 55x + 121\\\\= 25x -110x +121$

Hence, the product of the (5x-11)² is (25x²-110x+121).

Learn more about the Product:

brainly.com/question/6966983

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JulijaS [17]

Answer:

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Step-by-step explanation:

Given

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Required

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To do this, we make use of the following notations

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So:

$\frac{dA}{dt} = kA$

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$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

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Integrate both sides

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$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

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So, we have:

$A = Ce^{kt}$

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$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

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i.e.

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So:

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Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

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