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natima [27]
2 years ago
14

Choose the correct product of (5x − 11)2. 25x2 − 110x 121 25x2 − 121 25x2 121 25x2 110x 121.

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
5 0

Product is the multiplication of numbers. The product of the (5x-11)² is (25x²-110x+121).

<h3>What is a Product?</h3>

A product is the multiplication of a number or expression to another expression.

We know in order to find the product of (5x-11)², we need to multiply each of the terms inside the bracket to each term in the second bracket. therefore, the solution of the problem can be given as,

(5x-11)^2\\\\= (5x-11) \times (5x-11)\\\\= (5x \times 5x)-(5x \times 11)-(5x \times 11)(11 \times 11)\\\\= 25x^2 - 55x - 55x + 121\\\\= 25x -110x +121

Hence, the product of the (5x-11)² is (25x²-110x+121).

Learn more about the Product:

brainly.com/question/6966983

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Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

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Required

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To do this, we make use of the following notations

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So:

\frac{dA}{dt} = kA

Where k represents the constant of proportionality

\frac{dA}{dt} = kA

Multiply both sides by dt/A

\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}

\frac{dA}{A}  = k\ dt

Integrate both sides

\int\ {\frac{dA}{A}  = \int\ {k\ dt}

ln\ A = kt + lnC

Make A, the subject

A = Ce^{kt}

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So, we have:

A = Ce^{kt}

1000000 = Ce^{k*0}

1000000 = Ce^{0}

1000000 = C*1

1000000 = C

C =1000000

Substitute C =1000000 in A = Ce^{kt}

A = 1000000e^{kt}

To solve for k;

6\ years\ later = 500,000

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Take natural logarithm (ln) of both sides

ln(0.5) = ln(e^{k*6})

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k = \frac{-0.693}{6}

k = -0.1155

Recall that:

\frac{dA}{dt} = kA

Where

\frac{dA}{dt} = Rate

So, when

A = 600000

The rate is:

\frac{dA}{dt} = -0.1155 * 600000

\frac{dA}{dt} = -69300

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

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3 years ago
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