All categories

3 years ago

The solution(s) of ax2 + bx + c = 0 are also called its ____

Mathematics

2 answers:

BigorU [14]3 years ago

6 0

The solutions are also called its roots.

Leya [2.2K]3 years ago

3 0

Answer:

Roots of a Quadratic

Step-by-step explanation:

You might be interested in

Help me with maths please

jolli1 [7]

Answer:

i don't know this answer but i do know something about math i know a square plus b square = c square

Step-by-step explanation:

4 0

4 years ago

Solve: 4-(9g-5)=-27 please help

8_murik_8 [283]

Answer:

-2

Step-by-step explanation:

9g-4-5=-27

9g-9=-27

Add 9 to both sides

9g=-18

g=-2

4 0

3 years ago

Read 2 more answers

How do I solve this problem 3y-6+7y-4y

VashaNatasha [74]

Let's simplify step-by-step.
3y-6+7y-4y
=3y+ -6+7y+ -4
Combine Like Terms.
=3y+ -6 +7y+ -4y
=6y+ -6
Answer:
6y-6

6 0

4 years ago

g If the economy improves, a certain stock stock will have a return of 23.4 percent. If the economy declines, the stock will hav

dusya [7]

Answer:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

Step-by-step explanation:

We can define the random variable of interest X as the return from a stock and we know the following conditions:

$X_1 = 23.4 , P(X_1) =0.67$ represent the result if the economy improves

$X_2 = -11.9 , P(X_1) =0.33$ represent the result if we have a recession

We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing the data given we got:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

7 0

3 years ago

Pls someone answer because I’m not gonna be able to do this I’m going out of town pls help

Likurg_2 [28]

2 is B :::))))))))))))))))

7 0

3 years ago