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guajiro [1.7K]
3 years ago
8

Write the range of f(x) in all three notations if the domain is -2 < x < 6 . f(x)=x+3f(x)=x+3

Mathematics
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer:

Interval notation: Range = (1,9)

Words notation: Range is between 1 and 9.

Inequality notation: Range = {f(x)| 1 < f(x) < 9}

Step-by-step explanation:

The given function is

f(x)=x+3

We need to find the range of f(x) for the domain -2 < x < 6 .

At x=-2,

f(-2)=-2+3=1

At x=6,

f(6)=6+3=9

So, the range of the function is 1 < f(x) < 9. It can be written as

Interval notation: Range = (1,9)

Words notation: Range is between 1 and 9.

Inequality notation: Range = {f(x)| 1 < f(x) < 9}

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Find the value of b in the graph of y=3x+b if it is known that the graph goes through the point: N(0,5)
tino4ka555 [31]

Answer:

I believe b is 5.

Step-by-step explanation:

When you place the points in the values, you get 5=3(0)+b. When you simplify it, you get 5=b. I really hope this is correct, I apologize if it isn't! I hope this helps! :)

4 0
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If y varies inversely as x<br> and x = 4 when y = 15, find y when x=6
lord [1]

Answer:

y = 10

Step-by-step explanation:

Given y varies inversely as x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition x = 4 when y = 15 , then

15 = \frac{k}{4} ( multiply both sides by 4 )

60 = k

y = \frac{60}{x} ← equation of variation

When x = 6 , then

y = \frac{60}{6} = 10

7 0
3 years ago
What is the unit rate of 1/7 and 1/21 ? this is very confusing?
Xelga [282]

Answer:

the unit rate of 1/7 is itself (1/7), and for 1/21 is 1/21.

Step-by-step explanation:

this is because these rates/ratios are unit fractions. so if the numerater is 1, theres nothing you can do to simplify it.

you can check with the ceaser method as well, but you're still going to find the same solution.

plus, for example, if it takes 7 grams of sugar to make 1 cake, it wouldnt make sense for 1 gram of sugar to make 7 cakes.

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5 0
2 years ago
PLEASE HELP ME with an explanation. Thanks in advance
REY [17]

Answer:

3) 0.30

The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given  'A' plays a sport

          B work part time

Given P(A) = 0.48

         P(B)  = 0.40

        P(A∩B) =0.12

       P(A∪B)¹ =0.24

<u><em>Step(ii)</em></u>:-

By using conditional probability

P(B/A) = \frac{P(BnA}{P(A)}

and similarly P(A/B) = \frac{P(AnB}{P(B)}

The probability a randomly selected<em> student plays a sport</em> given they work part time

Now P(A/B) = \frac{P(AnB}{P(B)}

       P(A/B) = \frac{0.12}{0.40}= 0.30

<u>Final answer</u>:-

The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30

8 0
3 years ago
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