Answer:
The answer to your question is: I bought 7 snacks
Step-by-step explanation:
Data
beginning balance = $42 = b
lunch = $1.80 = l
snack = $ 0.85 = s
final balance = $0.05 = f
f = b - 1.8l - 0.05s
0.05 = 42 - 1.8l - 0.85s
After 20 days I spent = 1.8(20) in lunches = $36
0.05 = 42 - 36 - 0.85s
0.05 = 6 - 0.85s
0.05 - 6 = -0.85s
-5.95 = -0.85s
s = -5.95/-0.85
s = 7
Selecting 5 students to participate in a math contest would require combinations.
<u>SOLUTION:
</u>
given that, Selecting 5 students to participate in a math contest would require the calculating of a permutation or combination?
So, we need to differentiate between permutations and combinations.
Permutations - In mathematics, permutation is the act of arranging the members of a set into a sequence or order
Combinations - In mathematics, a combination is a selection of items from a collection, such that the order of selection does not matter.
So, now, for our math test, we just require students but not in an order nor with arrangements.
Hence, selecting 5 students to participate in a math contest would require combinations.
Would it be 61 ? i think i might be wrong
<em>(</em><em>A</em><em>)</em><em>2</em><em>8</em><em>4</em><em> </em><em>S</em><em>Q</em><em>U</em><em>A</em><em>R</em><em>E</em><em> </em><em>I</em><em>N</em><em>C</em><em>H</em><em>E</em><em>S</em><em> </em><em>I</em><em>S</em><em> </em><em>T</em><em>H</em><em>E</em><em> </em><em>S</em><em>U</em><em>R</em><em>F</em><em>A</em><em>C</em><em>E</em>