Work out 7/9 - 3/7what's the answer in its simplest form
2 answers:
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<h3>The probability of selecting a random student who is enrolled in both the courses is 0.280.</h3>
Step-by-step explanation:
Here, the total number of freshman in the university = 500
The number of students enrolled in Economics = n(E) = 323
The number of students enrolled in Mathematics = n(M) = 205
The number of students enrolled in Both Economics and math
= n(E∩M ) = 140
Let F : Event of selecting a student who is enrolled in both the courses
So, from the given data:
So, the probability of selecting a random students who is enrolled in both the courses is
Find the LCD 4 and 6 :
factor each denominator into its primes:
4 = 2²
6 = 2 * 3
Find the least common denominator 2² * 3 = 12
hope this helps!