<span><span>(<span><span>8x</span>+7</span>)</span>*<span>(<span><span>8x</span>+7</span>)</span></span>*<span>(<span><span>8x</span>+7</span><span>)
</span></span><span>(<span><span>8x</span>+7</span>)</span><span>(<span><span><span>64<span>x^2</span></span>+<span>112x</span></span>+49</span><span>)
</span></span><span><span><span><span><span><span><span>(<span>8x</span>)</span><span>(<span>64<span>x^2</span></span>)</span></span>+<span><span>(<span>8x</span>)</span><span>(<span>112x</span>)</span></span></span>+<span><span>(<span>8x</span>)</span><span>(49)</span></span></span>+<span><span>(7)</span><span>(<span>64<span>x^2</span></span>)</span></span></span>+<span><span>(7)</span><span>(<span>112x</span>)</span></span></span>+<span><span>(7)</span><span>(49)
</span></span></span><span><span><span><span><span>512<span>x^3</span></span>+<span>896<span>x^2</span></span></span>+<span>392x</span></span>+<span>448<span>x^2</span></span></span>+<span>784x</span></span>+<span>343
</span>Answer:
<span><span><span>512<span>x^3</span></span>+<span>1344<span>x^2</span></span></span>+<span>1176x</span></span>+<span>343</span>
Answer:
5 or 6
Step-by-step explanation:
So I did it in a different way than shown in rsm classes. I said that the speed was x-2 and x.
then I said the distance was 6 and 15. If the time taken was 1 hour more, then we can come up with this equation:
Since the time is 6/x-2 or 15/x
15/x-6/x-2=1
multiply everything to get a common denominator then cancel it out to get
(15x-30)-6x=x^2-2x
11x-30=x^2
x^2-11x+30=0
(x-5)(x-6) is factored form.
so x=5 or x=6. this means that the speed of the boat is either 5km/h or 6 km/h
Answer:
2√2
Step-by-step explanation:
We can find the relationship of interest by solving the given equation for A, the mean distance.
<h3>Solve for A</h3>

<h3>Substitute values</h3>
The mean distance of planet X is found in terms of its period to be ...

The mean distance of planet Y can be found using the given relation ...

The mean distance of planet Y is increased from that of planet X by the factor ...
2√2