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Greeley [361]
2 years ago
7

A unicycle travels 50 feet. If the radius of the tire is 24 INCHES, how many times does the tire rotate? A) about 8 times B) abo

ut 3 times C) about 4 times D) about 12 times
Mathematics
2 answers:
lbvjy [14]2 years ago
8 0

Answer:

<h2><em><u>The correct answer is C) about 4 times </u></em></h2><h2><em><u>Step-by-step explanation:</u></em></h2><h2><em><u>The tire rotates about 4 times. First calculate the circumference of the tire in feet (4π). Then divide 50 by 4π.</u></em></h2>

Pie2 years ago
6 0
The total distance traveled by cycle = 50 * 12 = 600 inch
1 complete rotation measures = 2 * 3.14 * 24 = 150.72 inch

Total rotation = 600 / 150.72
= approx. 4

In short, Your Answer would be Option C

Hope this helps!
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Rosey purchased 364 flowers to make centerpieces for a party. There are 13 tables. Each table will have 4 vases with the same nu
Olin [163]
7. honestly not 100% sure. i did 364 divided by 13 which was 28 so 28 flowers per table. and then 28 divided by 4. 7 flowers per vase.
8 0
2 years ago
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
3 years ago
Express 763636363636 as a rational number
shtirl [24]
x=0.7636363\ldots
10x=7.636363\ldots
1000x=763.636363\ldots

\implies1000x-10x=990x=756\implies x=\dfrac{756}{990}=\dfrac{42}{55}
4 0
2 years ago
Don't get this
kap26 [50]
I'll talk you through it so you can see why it's true, and then
you can set up the 2-column proof on your own:

Look at the two pointy triangles, hanging down like moth-wings
on each side of 'OC'.

-- Their long sides are equal,  OA = OB, because both of those lines
are radii of the big circle.

-- Their short sides are equal, OC = OC, because they're both the same line.

-- The angle between their long side and short side ... the two angles up at 'O',
are equal, because OC is the bisector of the whole angle there.

-- So now you have what I think you call 'SAS' ... two sides and the included angle of one triangle equal to two sides and the included angle of another triangle.
(When I was in high school geometry, this was not called 'SAS' ... the alphabet
did not extend as far as 'S' yet, and we had to call this congruence theorem
"broken arrow".)

These triangles are not congruent the way they are now, because one is
the mirror image of the other one.  But if you folded the paper along 'OC',
or if you cut one triangle out and turn it over, it would exactly lie on top of
the other one, and they would be congruent.

So their angles at 'A' and at 'B' are also equal ... those are the angles that
you need to prove equal.
5 0
3 years ago
Eleven more than six times a number is twenty-three
Natali5045456 [20]
11+6x=23 \\  \\ 11+6x-11=23-11 \\  \\ 6x=12 \\  \\  \frac{6x}{6}= \frac{12}{6}  \\  \\ x=2
4 0
2 years ago
Read 2 more answers
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