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Greeley [361]
2 years ago
7

A unicycle travels 50 feet. If the radius of the tire is 24 INCHES, how many times does the tire rotate? A) about 8 times B) abo

ut 3 times C) about 4 times D) about 12 times
Mathematics
2 answers:
lbvjy [14]2 years ago
8 0

Answer:

<h2><em><u>The correct answer is C) about 4 times </u></em></h2><h2><em><u>Step-by-step explanation:</u></em></h2><h2><em><u>The tire rotates about 4 times. First calculate the circumference of the tire in feet (4π). Then divide 50 by 4π.</u></em></h2>

Pie2 years ago
6 0
The total distance traveled by cycle = 50 * 12 = 600 inch
1 complete rotation measures = 2 * 3.14 * 24 = 150.72 inch

Total rotation = 600 / 150.72
= approx. 4

In short, Your Answer would be Option C

Hope this helps!
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3. A jogger runs 4 miles on Monday, 5 miles on
ki77a [65]

Answer:

17 miles

Step-by-step explanation:

4+5+5+3=17

5 0
2 years ago
Which equation shows the correct use of the Distributive Property? <br> −4(32x−12)=−15
KengaRu [80]

Answer:

-128x + 48 = -15

Step-by-step explanation:

I don't any  choices to pick from but using the distributive property you will multiply the -4 by everything in the parenthesis.

-4(32x - 12) = -15

=-128x + 48 = -15.

6 0
3 years ago
Read 2 more answers
Which system is equivalent to the system shown and could be used to solve the system of equations correctly using the eliminatio
Bumek [7]

Answer:

The solution is (2, -2)

Step-by-step explanation:

In order to solve this, multiply the second equation by -5 and then add through.

5x - 4y = 18

-5x - 15y = 20

------------------

-19y = 38

y = -2

Now that we have the value of y, we can solve for x.

x + 3y = -4

x + 3(-2) = -4

x - 6 = -4

x = 2

5 0
3 years ago
10. 10. If AB bisects CAF, and m&lt;EAF = 72°,<br>then the m&lt;BAF =​
never [62]

The measure of ∠BAF is 54°.

Solution:

DF and CE are intersecting lines.

m∠EAF = 72° and AB bisects ∠CAF.

∠EAF and ∠DAC are vertically opposite angles.

Vertical angle theorem:

<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>

∠DAC ≅ ∠EAF

m∠DAC = 72°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠DAE + m∠EAF = 180°

m∠DAE + 72° = 180°

Subtract 72° from both sides.

m∠DAE = 108°

∠CAF and ∠DAE are vertically opposite angles.

⇒ m∠CAF = m∠DAE

⇒ m∠CAF = 108°

AB bisects ∠CAF means ∠CAB = ∠BAF

m∠CAB + m∠BAF = 108°

m∠BAF + m∠BAF = 108°

2 m∠BAF = 108°

Divide by 2 on both sides, we get

m∠BAF = 54°

Hence the measure of ∠BAF is 54°.

4 0
3 years ago
If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?
Yuki888 [10]

Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

(C_x,C_y) ----> coordinates of point C

we have that

The horizontal distance AB is equal to

AB_x=10-2=8\ units

The vertical distance AB is equal to

AB_y=10-4=6\ units

Find the horizontal coordinate of point C

we know that

\frac{AC}{CB}=\frac{3}{1}

so

\frac{AC_x}{CB_x}=\frac{3}{1}

AC_x=3CB_x----> equation A

AC_x+CB_x=8 ----> equation B

substitute equation A in equation B

3CB_x+CB_x=8

4CB_x=8\\CB_x=2

AC_x=3(2)=6

so

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

C_x=A_x+AC_x=2+6=8

Find the vertical coordinate of point C

we know that

\frac{AC}{CB}=\frac{3}{1}

so

\frac{AC_y}{CB_y}=\frac{3}{1}

AC_y=3CB_y----> equation A

AC_y+CB_y=6 ----> equation B

substitute equation A in equation B

3CB_y+CB_y=6

4CB_y=6\\CB_y=1.5

AC_y=3(1.5)=4.5

so

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

C_y=A_y+AC_y=4+4.5=8.5

therefore

The coordinates of point C are (8,8.5)

5 0
2 years ago
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