1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kodGreya [7K]
3 years ago
12

Is the dilation of -3/4 a contraction or an expansion?

Mathematics
1 answer:
lyudmila [28]3 years ago
5 0
I don't under stand
You might be interested in
Screen printing a batch of shirts requires 1 minute per shirt in addition to 4 minutes of initial setup time. If it takes 30 min
HACTEHA [7]

6 shirts are in the batch

8 0
3 years ago
Will the sugar, the sand, or both dissolve in the water?
AleksandrR [38]

Answer:

sugar

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help me?<br><br> please and thank you!
JulsSmile [24]

Answer:

-1/12

Step-by-step explanation:

change divide sign to multiply by reciprocating

7 0
2 years ago
Ples help me find slant assemtotes
FrozenT [24]
A polynomial asymptote is a function p(x) such that

\displaystyle\lim_{x\to\pm\infty}(f(x)-p(x))=0

(y+1)^2=4xy\implies y(x)=2x-1\pm2\sqrt{x^2-x}

Since this equation defines a hyperbola, we expect the asymptotes to be lines of the form p(x)=ax+b.

Ignore the negative root (we don't need it). If y=2x-1+2\sqrt{x^2-x}, then we want to find constants a,b such that

\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0

We have

\sqrt{x^2-x}=\sqrt{x^2}\sqrt{1-\dfrac1x}
\sqrt{x^2-x}=|x|\sqrt{1-\dfrac1x}
\sqrt{x^2-x}=x\sqrt{1-\dfrac1x}

since x\to\infty forces us to have x>0. And as x\to\infty, the \dfrac1x term is "negligible", so really \sqrt{x^2-x}\approx x. We can then treat the limand like

2x-1+2x-ax-b=(4-a)x-(b+1)

which tells us that we would choose a=4. You might be tempted to think b=-1, but that won't be right, and that has to do with how we wrote off the "negligible" term. To find the actual value of b, we have to solve for it in the following limit.

\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-4x-b)=0

\displaystyle\lim_{x\to\infty}(\sqrt{x^2-x}-x)=\frac{b+1}2

We write

(\sqrt{x^2-x}-x)\cdot\dfrac{\sqrt{x^2-x}+x}{\sqrt{x^2-x}+x}=\dfrac{(x^2-x)-x^2}{\sqrt{x^2-x}+x}=-\dfrac x{x\sqrt{1-\frac1x}+x}=-\dfrac1{\sqrt{1-\frac1x}+1}

Now as x\to\infty, we see this expression approaching -\dfrac12, so that

-\dfrac12=\dfrac{b+1}2\implies b=-2

So one asymptote of the hyperbola is the line y=4x-2.

The other asymptote is obtained similarly by examining the limit as x\to-\infty.

\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0

\displaystyle\lim_{x\to-\infty}(2x-2x\sqrt{1-\frac1x}-ax-(b+1))=0

Reduce the "negligible" term to get

\displaystyle\lim_{x\to-\infty}(-ax-(b+1))=0

Now we take a=0, and again we're careful to not pick b=-1.

\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-b)=0

\displaystyle\lim_{x\to-\infty}(x+\sqrt{x^2-x})=\frac{b+1}2

(x+\sqrt{x^2-x})\cdot\dfrac{x-\sqrt{x^2-x}}{x-\sqrt{x^2-x}}=\dfrac{x^2-(x^2-x)}{x-\sqrt{x^2-x}}=\dfrac&#10; x{x-(-x)\sqrt{1-\frac1x}}=\dfrac1{1+\sqrt{1-\frac1x}}

This time the limit is \dfrac12, so

\dfrac12=\dfrac{b+1}2\implies b=0

which means the other asymptote is the line y=0.
4 0
3 years ago
Calculate the answer, express it in scientific notation.
castortr0y [4]
The first one
the first 2 numbers gives a power of 1 then the second gives you 1-4.
1+1-4 is -2 so its the first one
7 0
3 years ago
Other questions:
  • The length of a rectangular swimming pool is 10 feet longer than its width. If the perimeter of the pool is 100 feet, which of t
    13·2 answers
  • Express in logarithmic form for the base.. . 4^2=16
    10·2 answers
  • Help with Probability!!
    6·2 answers
  • Simplify x^2+3x+2/x+1<br><br> A. X+2<br> B. X-2<br> C. X^2+1<br> D. X^2-1
    15·1 answer
  • (5.13x10^-2)-(3.9x10^-3)
    14·1 answer
  • Tamara’s dosage of medication has recently decreased 20 milligrams per day. What is the total decrease in Tamara’s medication at
    12·1 answer
  • List L consists of numbers 1, square root of 2, x, and x^2 , where x&gt;0, and the range of the numbers in list L is 4. Which qu
    12·1 answer
  • Which of the following equations describes the line
    5·1 answer
  • Pls help ill give brainly
    15·2 answers
  • Of the numbers 7, 8, 9, and 10, which is a solution to the inequality n – 5 &lt; 3? Hurry Plz
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!