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Tems11 [23]
2 years ago
11

A necklace has and matching bracelet have two types of beads. The necklace has 12 large beads and 8 small beads and weighs 88 gr

ams. The bracelet has 5 large beads and 2 small beads and weighs 25 grams. Write and solve a system of equations to find the weight of a large bead and weight of a small bead.
Mathematics
1 answer:
miv72 [106K]2 years ago
5 0

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Step-by-step explanation:

Let,

Weight of one large bead = x

Weight of one small bead = y

According to given statement;

12x+8y=88     Eqn 1

5x+2y=25      Eqn 2

Multiplying Eqn 2 by 4

4(5x+2y=25)\\20x+8y=100\ \ \ Eqn\ 3\\

Subtracting Eqn 1 from Eqn 3

(20x+8y)-(12x+8y)=100-88\\20x+8y-12x-8y=12\\8x=12

Dividing both sides by 8

\frac{8x}{8}=\frac{12}{8}\\x=1.5

Putting x=1.5 in Eqn 1

12(1.5)+8y=88\\18+8y=88\\8y=88-18\\8y=70

Dividing both sides by 8

\frac{8y}{8}=\frac{70}{8}\\y=8.75

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/11334714
  • brainly.com/question/11345547

#LearnwithBrainly

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Answer:

The answer is shown below

Step-by-step explanation:

Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor.

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b)

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c) At y = 75% = 0.75

y=\frac{1}{1+9e^{-0.8959t}}\\0.75=\frac{1}{1+9e^{-0.8959t}}\\t=3.68\ days

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