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BabaBlast [244]
2 years ago
8

Can someone help me find the angles of R, S, and U? ive already solved the other ones

Mathematics
1 answer:
igomit [66]2 years ago
7 0
Assuming the angle congruent to r is not a right angle, we can solve for a supplementary one.

70 + x + x=180

70 + 110=180

110 can be broken down into 55, which we can use for the other two sides.

I’m gonna assume angle R is 55°.

For angle S, same thing. 62 + x=180

The value for it is 118, half it and you get 59°.

Last but not least, angle u. Angle u is diff bc it’s complimentary. We know that one side equals 59°, so subtract 59 from 90, and the value of angle U is 31°.

Hope this helps! It’s been a while since I was in geometry so I hope I’m right too aha
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1

Step-by-step explanation:

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factors of 19: 1,19

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3 years ago
If (sin(()−1))p =2cos(()−1)q , show that p​^2​​ =4q​^2 (1− q^2) ?.
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Likely the equation is

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\sin(\sin^{1}p)=\sin(2\cos^{-1}q)
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as required.
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4 years ago
A tire company has developed a new type of steel-belted radial tire. Extensive testing indicates the population of mileages obta
Andru [333]

Answer:

Step-by-step explanation:

According to the given question, a tire company has developed a new type of steel-belted radial tire. Extensive testing indicates the population of mileages obtained by all tires of this new type is normally distributed with a mean of 37,000 miles and a standard deviation of 3,887 miles.

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X ~ (μ = 37000, σ =3,887)

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P(X < k) = 0.02

\Rightarrow P\left ( \frac{X-\mu }{\sigma }\leq \frac{k-\mu }{\sigma } \right )=0.02&#10;\\\\P\left ( Z \leq \frac{k-37,000 }{3,887 } \right )=0.02

From the standard normal curve 2% area is determined as -2.0537 and hence

\frac{k-37,000}{3,887}=-2.0537\\\\k=37000-7982.7319\\\\k=29017.2681\\\\\Rightarrow k=29018

If we consider z value at two decimal places then

\frac{k-37,000}{3,887} =-2.05\\\\\Rightarrow k=29032&#10;

Therefore the  guaranteed 29032 mileage be if the tire company desires that no more than 2 percent of the tires will fail to meet the guaranteed mileage.

The area under the standard normal curve is determined as:

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